Concept explainers
An expression for the magnitude of the magnetic field in three separate regions of space; inside the inner conductor, between the two conductors, outside of the outer conductor
Answer to Problem 58QAP
Explanation of Solution
Given:
Radius of the inner conductor = Ri
Radius of outer
Formula used:
Calculation:
To find the field inside the inner conductor we should consider an Amperian loop of radius
Cross sectional area of Amperian loop =
Cross sectional area of the inner conductor =
Area of Amperian loop is less than the area of inner conductor. So current through the loop is a fraction of the total current i.
To find the field between the conductors we should consider a Amperian loop of radius r, where
The Amperian loop encloses the entire inner conductor, so
To find the field outside of the cable we should consider an Amperian loop with radius r, where
Since the current flows are in opposite directions, the net current through the loop is zero.
So,
Conclusion:
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Chapter 19 Solutions
COLLEGE PHYSICS
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