Concept explainers
(a)
Current in the dryer
Answer to Problem 76QAP
Current in the dryer=
Explanation of Solution
Given info:
Formula used:
Calculation:
Conclusion:
Current in the dryer=
(b)
Resistance in the dryer
Answer to Problem 76QAP
Resistance in the dryer=
Explanation of Solution
Given info:
Formula used:
Calculation:
Conclusion:
Resistance in the dryer=
(c)
Magnetic field does the dryer produce at the user's head
Answer to Problem 76QAP
Magnetic field does the dryer produce at the user's head=
There's a possibility of health concerns due to the use of hair dryer
Explanation of Solution
Given info:
Formula used:
Calculation:
Comparison with Earth's magnetic field,
There's a possibility of health concerns due to the use of hair dryer
Conclusion:
Magnetic field does the dryer produce at the user's head=
There's a possibility of health concerns due to the use of hair dryer
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Chapter 19 Solutions
COLLEGE PHYSICS
- An example of magnetohydrodynamics (MHD) comes from the flow of a river (salty water). This fluid interacts with the Earth’s magnetic field to produce a potential difference between the two river banks. How would you go about calculating the potential difference?arrow_forwardThe following statements are related to the force of a magnetic field on a current-carrying wire. Indicate whether each statement is true (T) or false (F). (a) The magnetic force on the wire is independent of the direction of the current. (b) The force on the wire is directed perpendicular to both the wire and the magnetic field. (c) The force takes its largest value when the magnetic field is parallel to the wire.arrow_forward(a) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength magnetic field is needed to hold antiprotons, moving at 5.00107m/s in a circular path 2.00 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge. (b) Is this field strength obtainable with today’s technology or is it a futuristic possibility?arrow_forward
- Construct Your Own Problem Consider a mass separator that applies a magnetic field perpendicular to the velocity of ions and separates the ions based on the radius of curvature of their paths in the field. Construct a problem in which you calculate the magnetic field strength needed to separate two ions that differ in mass, but not charge, and have the same initial velocity. Among the things to consider are the types of ions, the velocities they can be given before entering the magnetic field, and a reasonable value for the radius of curvature of the paths they follow. In addition, calculate the separation distance between the ions at the point where they are detected.arrow_forwardWhat is the direction of the magnetic field that produces the magnetic force on a positive charge as shown in each of the three cases in the figure below, assuming B is perpendicular to V?arrow_forwardHow far from the starter cable of a car, carrying 150 A, must you be to experience a field less than the Earth's (5.00105T) ? Assume a long straight wire carries the current. (In practice, the body of your car shields the dashboard compass.)arrow_forward
- Classify each of die following statements as a characteristic (a) of electric forces only, (b) of magnetic forces only, (c) of both electric and magnetic forces, or (d) of neither electric nor magnetic forces. (i) The force is proportional to the magnitude of the field exerting it. (ii) The force is proportional to the magnitude of the charge of the object on which the force is exerted. (iii) The force exerted on a negatively charged object is opposite in direction to the force on a positive charge. (iv) The force exerted on a stationary charged object is nonzero. (v) The force exerted on a moving charged object is zero. (vi) The force exerted on a charged object is proportional to its speed. (vii) The force exerted on a charged object cannot alter the objects speed. (viii) The magnitude of the force depends on the charged objects direction of motion.arrow_forwardWhat is the direction of the magnetic force on a positive charge that moves as shown in each of the six cases shown in Figure 22.59?arrow_forwardWhat is the direction of the velocity of a negative charge that experiences the magnetic force shown in each of the three cases in Figure 22.51, assuming it moves perpendicular to B?arrow_forward
- Find the magnitude and direction of the magnetic field at the point equidistant from the wires in Figure 22.58(b), using the rules of vector addition to sum the contributions from each wire.arrow_forwardCertain experiments must be performed in the absence of any magnetic fields. Suppose such an experiment is located at the center of a large solenoid oriented so that a current of I = 1.00 A produces a magnetic field that exactly cancels Earths 3.50 105 T magnetic field. Find the solenoids number of turns per meter.arrow_forwardThe right-hand rule is a way to determine the direction of the magnetic field produced by moving charges. Imagine wrapping your right hand around the path of the charges so that the positive charges (or the current) flow from the little finger side of your fist to the thumb side (Figure 8.53). Then your fingers circle the path in the same direction as the magnetic field lines. Use this rule to verify the directions of the magnetic fields shown in Figures 8.8 and 8.10. How would you use the rule to find the direction of the magnetic field lines around a moving negative charge?arrow_forward
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