The three methods of traversing a binary tree are pre-order, post-order and in-order traversal.

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The three methods of traversing a binary tree are pre-order, post-order and in-order traversal.

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CO LL * Question Completion Status: QUESTION 3 Write a recursive function, OnlyChild(..), that returns the number of nodes in a binary tree that has only one child. Consider binaryTreeNode structure is defined as the following. struct binaryTreeNode int info; binaryTreeNode *llink: binaryTreeNode *rlink; The function is declared as the following. You must write the function as a recursive function. You will not get any credits if a non-recursive solution is used. int OnlyChild(binaryTreeNode *p); For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). Paragraph Arial 10pt B. ^三へ三三山三Ex? X2 = E E E 9 Click Save and Submit to save and submit. Click Save All Answers to save all ansuwers. Is E English (United States) Focus || 15 stv MacBook Air D00 O00 F4 F5 F8 64

#ifndef BT_NODE_H#define BT_NODE_H struct btNode{ int data; btNode* left; btNode* right;}; // pre: bst_root is root pointer of a binary search tree (may be 0 for// empty tree) and portArray has the base address of an array large// enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data// values are written (as they are encountered) to portArray in// increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex); // pre: (none)// post: dynamic memory of all the nodes of the tree rooted at root has been// freed up (returned back to heap/freestore) and the tree is now empty// (root pointer contains the null address)void tree_clear(btNode*& root); // pre: (none)// post: # of nodes contained in tree rooted at root is returnedint…

Assume the tree node structure is following........ struct node { int data; struct node* left; struct node* right; }; struct node *root = null; and there is a created new node function, called newnode(int new_data). Please filled the Blank of Insertion function. void insert(struct node *root, int key) { struct node *current; queue q; q.enque(root); while(!q.empty() } current = q.front(); q.deque(); if(current->left == NULL) { break; } else } q.enque( if(current->right == NULL) { break; else q.enque(_ = newnode(key); = newnode(key); _-));