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Consider the left side of the box as Consisting of N small pieces. Let
Write an expression for the net electric flux
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- A solid insulating plastic sphere of radius a carries atotal net positive charge 3Q uniformly distributed throughout its interior.The insulating sphere is coated with a metallic layer of inner radius a andouter radius 2a. The conducting metallic layer carries a net charge of -2Q. Apply Gauss’s law to find the magnitude of the electric field in the region r < a. Inthe figure, draw the Gaussian surface you are using, and indicate on that surface the direction of anyvectors which appear in the mathematical expression of Gauss’s law. Express your answer in terms ofa, Q, r, and ε0. (If you get an expression involving ρ, substitute it from above to re-express youranswer in terms of the stated variables.)arrow_forwardA plane with a circular hole of radius R is uniformly charged with areal density o. Find the strength E of the electric field on the axis of the hole as a function of the distance h to its center. Hint: Use the principle of wwwmm superposition.arrow_forwardTwo rings of radius R-5 cm are 34 cm apart and concentric with a common vertical axis (figure below). Ring 1 carries a uniformly distributed charge Q₁ = 20 nC and ring 2 carries a uniformly distributed charge of Q₂ = -70 nC. T A Ring 2 Ring 1 1. Find the magnitude of the electric field E created by Ring 1 at point A, halfway between the two rings. E₁ = [N/C] What is the direction of the electric. 2. field E, created by Ring 1 at point A. Direction: + 3. Write the expression of the electric filed E₁ created by Ring 1 at point A. E₁ = [N/C] > [N/C] 7. If vector E₁ = [N/C] and vector Ē₂ = [N/C]. Find the net electric filed Enet at point A. Ēnet = [N/C] 8. If a charge q = 5 nC is placed at location A, what would be the force on this charge? Use the answer of question 7.arrow_forward
- A non-uniform thin rod is bent into an arc of radius R. The linear charge density λ of the rod depends on θ and is given byλ= λ0/cos θwhere λ0 is a positive constant. The arc extends from θ = π/2 to θ = 3π/2 Sketch the direction of the resultant electric field at the origin.Calculate the magnitude of the electric field E⃗ .arrow_forwardAnswer letters c and d.arrow_forwardAn insulating solid sphere of radius a has a uniform bulk density ρ and a total positive charge Q. Calculate the magnitude of the electric field at a point outside the sphere.arrow_forward
- Consider an infinitely long, hollow cylinder, with inner radius R1 and outer radius Ra. the material of the cylinder is uniformly charged so that the cylinder has a charge per length. Finally, consider a solid cylinder of radius R, with a uniform charge density. What is the magnitude of the electric field inside the cylinder at a distance r from the center (r<R)?arrow_forwardAs shown in Figure, a particle of charge +Q produces an electric field of magnitude Epart at point P, atdistance R from the particle. As in figure b, that same amount of charge is spread uniformly along a circulararc that has radius R and subtends an angle ?. The charge on the arc produces an electric field of magnitudeEarc at its center of curvature P. For what value of ? does Earc = 0.50 Epart ?arrow_forwards of the 15.13 The Coaxial Cable. A long coaxial cable con- sists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b and outer eld also radius c. The outer cylinder is mounted on insulating supports and has no net charge. The inner cylinder has a uniform positive charge per unit length A. Calculate the electric field a) at any point between the cylinders, a distance r from the axis; b) at any point outside the outer cylinder. c) Graph the magnitude of the electric field as a function of the distance r from the axis of the cable, from r=0 to r = 2c. d) Find the charge per unit length on the inner surface and on the outer surface of -ntained by the can you %3D the outer cylinder.arrow_forward
- In a uniform electric field of magnitude E, the field lines cross through a rectangle of area A at an angle of 32.9° with respect to the plane of the rectangle. What is the flux through the rectangle?arrow_forwardDon't use chatgpt.arrow_forwardTwo long straight parallel rods, #1 and #2, carry uniform positive linear charge densities. The charge density on rod #2 is twice as great as the charge density on rod #1. The locus of points where the electric field due to these rods is zero is: along a line perpendicular to rods #1 and #2. the electric field cannot be zero between the two rods. at any point midway between the rods. O along a line between the two rods, closer to rod #2 than rod #1. O along a line between the two rods, closer to rod # 1 than rod #2.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
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