(a) Interpretation: The given number should be converted into standard scientific notation. 102.3 × 10 − 5 Concept Introduction: Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10. For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
(a) Interpretation: The given number should be converted into standard scientific notation. 102.3 × 10 − 5 Concept Introduction: Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10. For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
The given number should be converted into standard scientific notation.
102.3×10−5
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
1.023×10−2.
Explanation of Solution
The given number is 102.3×10−5, to write it in scientific notation, decimal is placed after first non-zero digit. After placing the decimal, there will be three digits after the decimal thus, power of 10 will be increased by + 3 and scientific notation will be 1.023×10−2 (-5+3 = -2).
Interpretation Introduction
(b)
Interpretation:
The given number should be converted into standard scientific notation.
32.03×10−3
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
3.203.
Explanation of Solution
The given number is 32.03×10−3, to write it in scientific notation, decimal is placed after first non-zero digit. After placing the decimal, thus, three units are added to the power of 10. The power of 10 becomes + 3 and scientific notation will be 3.203 as power of 10 is -3 and after placing the decimal then + 3 is added to the power of 10, thus power of 10 is equal to 0. Hence, 3.203 is the standard scientific notation.
Interpretation Introduction
(c)
Interpretation:
The given number should be converted into standard scientific notation.
59933×102
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
5.9933×106.
Explanation of Solution
The given number is 59933×102, to write it in scientific notation, decimal is placed after first non-zero digit. Thus, after placing the decimal, there will be four digits after the decimal, thus, power of 10 will be increased by four units, and overall power of 10 will be + 2+4 = 6. Thus, standard scientific notation is 5.9933×106.
Interpretation Introduction
(d)
Interpretation:
The given number should be converted into standard scientific notation.
599.33×104
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
5.9933×108.
Explanation of Solution
The given number is 599.33×104, to write it in scientific notation, decimal is placed after first non-zero digit. Thus, after placing the decimal, there will be four digits after the decimal, thus, power of 10 will be increased by four units, and overall power of 10 will be + 4+4 = 8. Thus, standard scientific notation is 5.9933×108.
Interpretation Introduction
(e)
Interpretation:
The given number should be converted into standard scientific notation.
5993.3×103
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
5.9933×107.
Explanation of Solution
The given number is 5993.3×103, to write it in scientific notation, decimal is placed after first non-zero digit. Thus, after placing the decimal, there will be four digits after the decimal, thus, power of 10 will be increased by four units, and overall power of 10 will be + 3+4 = 7. Thus, standard scientific notation is 5.9933×107.
Interpretation Introduction
(f)
Interpretation:
The given number should be converted into standard scientific notation.
2054×10−1
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
2.054×102.
Explanation of Solution
The given number is 2054×10−1, to write it in scientific notation, decimal is placed after first non-zero digit. After placing the decimal, there will be three digits after the decimal thus, power of 10 will be + 3 and thus, overall power of 10 will be + 3-1=+2. Hence, standard scientific notation is 2.054×102.
Interpretation Introduction
(g)
Interpretation:
The given number should be converted into standard scientific notation.
32, 000, 000×10−6
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
3.2×101.
Explanation of Solution
The given number is 32, 000, 000×10−6, to write it in scientific notation, decimal is placed after first non-zero digit. After placing the decimal, there will be seven digits after the decimal thus, power of 10 will be + 7 and thus, overall power of 10 will be + 7-6=+1. Hence, standard scientific notation is 3.2×101.
Interpretation Introduction
(h)
Interpretation:
The given number should be converted into standard scientific notation.
59.933×105
Concept Introduction:
Scientific notation for a number is written in such a way that large numbers are written in small decimal form which is then multiplied by the power of 10.
For numbers less than 1, the power of 10 in scientific notation has negative exponent and for numbers greater than 1, the power is either zero or has positive exponent.
Expert Solution
Answer to Problem 121AP
5.9933×109.
Explanation of Solution
The given number is 59.933×105, to write it in scientific notation, decimal is placed after first non-zero digit. Thus, after placing the decimal, there will be four digits after the decimal, thus, power of 10 will be increased by four units, and overall power of 10 will be + 4+5 = 9. Thus, standard scientific notation is 5.9933×109.
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For the following questions (Q1-Q5), consider the compound tartrazine (Yellow 5 food dye) that has a chemical formula of C16H9N4Na3O9S2. Ana weighs out 0.1328 g of tartrazine powder on the balance for her experiment and makes a stock solution by dissolving her powder in 500.0 mL of solution.
Q1. Determine the number of moles of tartrazine that Ana weighed out.
answer for (Q1)= 2.487 x 10^-4 moles of tartrazine
*****need Q2 answered*******
Q2. Find the molarity (mol/L) of Ana’s tartrazine solution.
Concentration (µM or µmol/L)
Absorbance
0.00
0.001
9.94
0.252
19.9
0.506
29.8
0.738
39.8
1.018
slope (m): 0.02534 1/(µM)
y-intercept (b): -0.0009147
In the reaction:
KClO3(aq) + 5KCl(aq) + 6HNO3(aq) → 6KNO3(aq) + 3Cl2(g) + 3H2O(l)
How many grams of KClO3 are required to prepare 10.0 g of Cl2? Report your answer in standard notation using 3 significant figures.
Mass of Empty Beaker is 141.2g, Beaker + Water is 388.3g, mass of water is 247.1g, volume of water is 0.2471mL, calculate volume H2=Volume displaced water
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