Figure 2-16 gives the velocity of a particle moving on an x axis. What are (a) the initial and (b) the final directions of travel? (c) Does the particle stop momentarily? (d) Is the acceleration positive or negative? (e) Is it constant or varying? Figure 2-16 Question 1.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

100%

Chapter 2, Problem 1Q

Figure 2-16 gives the velocity of a particle moving on an x axis. What are (a) the initial and (b) the final directions of travel? (c) Does the particle stop momentarily? (d) Is the acceleration positive or negative? (e) Is it constant or varying?

Chapter 2, Problem 1Q, Figure 2-16 gives the velocity of a particle moving on an x axis. What are a the initial and b the

Figure 2-16 Question 1.

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:10

Students have asked these similar questions

A particle's position on the x axis of Fig. 2-1 is given byx = 4 - 27t + t3,with x in meters and t in seconds.(a) Because position x depends on time t, the particle must be moving. Find the particle's velocity function v(t) and acceleration function a(t).(b) Is ?there ever a time when v = 0

A particle moves from an initial position with coordinates x = -2.0 m, y = +3.0 m, to a final position with coordinates x = +5.0 m, y = +7.0 m in a time interval of 10 s. What is the magnitude of the average velocity for this displacement?

An object is thrown vertically upwards by a person’s hands. While it is in contact with their hand, the object has an acceleration of ?=(2.00t^2+12.0t) m/s^2, with an initial velocity of zero. It is in contact with the person’s hands for 1.2 s. How high above the point of release does this object go? Ignore the air resistance and height change due to the motion of the hand.

Answer 2

Textbook Question

100%

Chapter 2, Problem 1Q

Figure 2-16 gives the velocity of a particle moving on an x axis. What are (a) the initial and (b) the final directions of travel? (c) Does the particle stop momentarily? (d) Is the acceleration positive or negative? (e) Is it constant or varying?

Chapter 2, Problem 1Q, Figure 2-16 gives the velocity of a particle moving on an x axis. What are a the initial and b the

Figure 2-16 Question 1.

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:10

Answer 3

Textbook Question

100%

Chapter 2, Problem 1Q

Figure 2-16 gives the velocity of a particle moving on an x axis. What are (a) the initial and (b) the final directions of travel? (c) Does the particle stop momentarily? (d) Is the acceleration positive or negative? (e) Is it constant or varying?

Chapter 2, Problem 1Q, Figure 2-16 gives the velocity of a particle moving on an x axis. What are a the initial and b the

Figure 2-16 Question 1.

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:10

Answer 4

Textbook Question

100%

Chapter 2, Problem 1Q

Figure 2-16 gives the velocity of a particle moving on an x axis. What are (a) the initial and (b) the final directions of travel? (c) Does the particle stop momentarily? (d) Is the acceleration positive or negative? (e) Is it constant or varying?

Chapter 2, Problem 1Q, Figure 2-16 gives the velocity of a particle moving on an x axis. What are a the initial and b the

Figure 2-16 Question 1.

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:10

Answer 5

Textbook Question

100%

Answer 6

Textbook Question

100%

Answer 7

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Answer 8

Expert Solution & Answer

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To find:

a) Initial direction of travel.

b) Final direction of travel.

c) Does the particle stop momentarily?

d) Is the acceleration positive or negative?

e) Is the acceleration constant or varying?

Answer 12

Answer to Problem 1Q

Solution:

a) Initial direction of travel is negative.

b) Final direction of travel is positive.

c) The particle stops momentarily.

d) The acceleration is positive.

e) The acceleration is constant.

Answer 13

Explanation of Solution

1) Concept:

After reading the graph, we can say that the Initial direction of travel is negative. As compared to that final direction of travel is positive.

As for an instance the velocity of the particle is zero, it indicates that the particle stops momentarily.

From the graph, we can say that the acceleration is positive and constant as the graph is a straight line and ascending in positive direction.

2) Given:

Graph in Fig 2.16.

3) Calculations:

a) When we look at the graph, it is starting below the x-axis, which states that the initial direction of travel would be negative.

b) When we look at the graph, it is ending above the x-axis, which states that the final direction of travel would be positive.

c) When we say it stops momentarily, it means the velocity of the particle is zero for a moment. When we look at the graph, the velocity is zero for one point, so we can say that the particle stops momentarily.

d) Now as the graph is moving from negative velocity to positive velocity, it means the velocity is increasing. From the above statement, we can say that the acceleration is positive.

e) As the graph is a straight line, the acceleration is constant.

Conclusion:

We have been given the graph of velocity vs time. From this graph, we can find the acceleration of the object by finding the slope of the graph. Looking at the nature of the graph, we can also conclude the direction of the acceleration and velocity at any given point.