(a)
Interpretation: The name of the technique for the separation of table salt and pepper is to be interpreted.
Concept introduction:
A mixture consists of two or more components that can be physically separated into their respective components. The mixture can be categorized as homogeneous or heterogeneous depending on how uniform it is.
There are several separation techniques used to separate the components of the mixture. Some common examples of separation techniques are evaporation, distillation, fractional distillation, etc.
(b)
Interpretation: The name of the technique for the separation of drinking water contaminated with soot is to be interpreted.
Concept introduction:
A mixture consists of two or more components that can be physically separated into their respective components. The mixture can be categorized as homogeneous or heterogeneous depending on how uniform it is.
There are several separation techniques used to separate the components of the mixture. Some common examples of separation techniques are evaporation, distillation, fractional distillation, etc.
(c)
Interpretation: The name of the technique for the separation of crushed ice and crushed glass is to be interpreted.
Concept introduction:
A mixture consists of two or more components that can be physically separated into their respective components. The mixture can be categorized as homogeneous or heterogeneous depending on how uniform it is.
There are several separation techniques used to separate the components of the mixture. Some common examples of separation techniques are evaporation, distillation, fractional distillation, etc.
(d)
Interpretation: The name of the technique for the separation of table sugar dissolved in ethanol is to be interpreted.
Concept introduction:
A mixture consists of two or more components that can be physically separated into their respective components. The mixture can be categorized as homogeneous or heterogeneous depending on how uniform it is.
There are several separation techniques used to separate the components of the mixture. Some common examples of separation techniques are evaporation, distillation, fractional distillation, etc.
(e)
Interpretation: The name of the technique for the separation of two pigments (chlorophyll a and chlorophyll b) is to be interpreted.
Concept introduction:
A mixture consists of two or more components that can be physically separated into their respective components. The mixture can be categorized as homogeneous or heterogeneous depending on how uniform it is.
There are several separation techniques used to separate the components of the mixture. Some common examples of separation techniques are evaporation, distillation, fractional distillation, etc.
Want to see the full answer?
Check out a sample textbook solutionChapter 2 Solutions
MOLECULAR NATURE OF MATTER ALEKS ACCESS
- Describe in words and by means of complete chemical equations, how a mixture of 1.25 g of benzoic acid tertbutylbenzene can be separated by applying the separation of 2 components by liquid-liquid extraction.arrow_forwardA STOCK SOLUTION containing 0.1581 g/L K2CrO4 was prepared.In order to make the CALIBRATION STANDARD, 5 ml of the STOCK was transferredinto a 50ml volumetric flask and then diluted with an appropriate solvent.Calculate:(a) The ppm of K2CrO4 in the CALIBRATION STANDARD.(b) The molarity of K2CrO4 in the CALIBRATION STANDARD. (c) Calculate the molar absorptivity of K2CrO4 (at 371.0 nm). Assume that Beer's Law isobeyed over this concentration range.At 371.0 nm, this CALIBRATION STANDARD in a cell of path length 1.00 cm gave a %T of 59.752.arrow_forward4.(a) Aqueous 50.5 % (w/w) sodium hydroxide has a density of 1.53 g cm–3. Calculate the concentration of this solution in mol dm–3. (b) What volume of 50.5 % (w/w) aqueous sodium hydroxide is required to prepare 500 cm3 of 0.100 mol dm–3 stock NaOH? [Start with your answer to 4(a)]arrow_forward
- (b) The distribution ratio for X between n-hexane and water is 8.9. Calculate the concentration of X remaining in the aqueous phase after 50.0 mL of 0.200 M X is treated by extraction with the following quantities of n-hexane?arrow_forwardA 25.00mL wastewater sample was analyzed for its Mg2+ content using a standard gravimetric method. the sample was diluted to 3.00L and an 11.00mL aliquot was treated to precipitate magnesium as MgNH4PO4.6H2O using (NH4)2HPO4 as the precipitating agent. the precipitate was then filtered, washed, dried, and ignited resulting in a 0.1325mg Mg2P2O7 residue. How much Mg (in ppm) is present in the original samplearrow_forward4) Given the following analyses of groundwater (reported as mg/L): Ca²+ = 16.5; Mg2+ = 3.1; Na = 13; K+ = 2.6; (bicarbonate) HCO3 = 67; SO4² = 18; Cl = 5.9, and SiO₂ (uncharged species) = 35 a. Calculate the analytical error of this set of analyses. b. Calculate the total dissolved solids (TDS) of the solution (sum concentration as mg/L for all species)?arrow_forward
- When a Vitamin C (ascorbic acid; MM = 176.12 g mol-1) tablet is crushed, dissolved and titrated with 0.0340 M KIO3(aq) to a purple/blue endpoint (given by a starch indicator), the volume of KIO3 used is 29.80 mL. If 60 mg of ascorbic acid is the recommended dietary allowance (i.e., 100% of the RDA), then what is the % RDA for the Vitamin C in the tablet? KIO3(aq) + 5 KI + 6 H+ → 3 I2(aq) + 3 H2O I2 (aq) + ascorbic acid → 2 I- + dehydroascorbic acidarrow_forwardProvide a complete and detailed separation scheme for the following compounds, you have the following chemicals: 1.0M NaOH, 1.0M HCl, THF, H2O. Consider you have any standard glassware and a separatory funnel.arrow_forwardOral rehydration salts are stated to contain the following components: Sodium Chloride 3.5g Potassium Chloride 1.5g Sodium Citrate 2.9g Anhydrous Glucose 20.0g 8.342 g of oral rehydration salts are dissolved in 500 ml of water. 5 ml of the solution is diluted to 100 ml and then 5 ml is taken from the diluted sample and is diluted to 100 ml. The sodium content of the sample is then determined by flame photometry. The sodium salts used to prepare the mixture were: Trisodium citrate hydrate (C6H5Na3O7, 2H2O) MW 294.1 and sodium chloride (NaCl) NW 58.5. Atomic weight of Na = 23. The content of Na in the diluted sample was determined to be 0.3210 mg/100 ml. Determine the % of stated content of Na in the sample. The stated should be 104.5, how??arrow_forward
- an ecobotanist separates the components of a tropical barkextract by chromatography. She discovers a large proportion ofquinidine, a dextrorotatory isomer of quinine used for control of arrhythmic heartbeat. Quinidine has two basic nitrogens (K(b1)=4.0X10⁻⁶ and K(b2)=1.0X10⁻¹⁰). To measure theconcentration, she carries out a titration. Because of the low solubility of quinidine, she first protonates both nitrogens withexcess HCl and titrates the acidified solution with standardized base. A 33.85-mg sample of quinidine (M=324.41g/mol) isacidified with 6.55 mL of 0.150 MHCl.(c) What is the pH at the first equivalence point?arrow_forwardAn ecobotanist separates the components of a tropical barkextract by chromatography. She discovers a large proportion ofquinidine, a dextrorotatory isomer of quinine used for control of arrhythmic heartbeat. Quinidine has two basic nitrogens (K(b1)=4.0X10⁻⁶ and K(b2)=1.0X10⁻¹⁰). To measure theconcentration, she carries out a titration. Because of the low solubility of quinidine, she first protonates both nitrogens withexcess HCl and titrates the acidified solution with standardized base. A 33.85-mg sample of quinidine (M=324.41g/mol) isacidified with 6.55 mL of 0.150 MHCl.(a) How many milliliters of 0.0133 MNaOH are needed to titrate the excess HCl?(b) How many additional milliliters of titrant are needed to reach the first equivalence point of quinidine dihydrochloride?(c) What is the pH at the first equivalence point?arrow_forwardOral rehydration salts are stated to contain the following components: Sodium Chloride 3.5g Potassium Chloride 1.5g Sodium Citrate 2.9g Anhydrous Glucose 20.0g 8.342 g of oral rehydration salts are dissolved in 500 ml of water. 5 ml of the solution is diluted to 100 ml and then 5 ml is taken from the diluted sample and is diluted to 100 ml. The sodium content of the sample is then determined by flame photometry. The sodium salts used to prepare the mixture were: Trisodium citrate hydrate (C6H5Na3O7, 2H2O) MW 294.1 and sodium chloride (NaCl) NW 58.5. Atomic weight of Na = 23. The content of Na in the diluted sample was determined to be 0.3210 mg/100 ml. Determine the % of stated content of Na in the sample.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY