Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change
Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change
7th Edition
ISBN: 9780078129865
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 2, Problem 2.137P
Interpretation Introduction

Interpretation:

The masses of all possible 1+ ions for boron trifluoride are to be calculated.

Concept introduction:

Mass spectrometry is a technique used to analyze the structure and chemical properties of different molecules. In this technique, molecules are bombarded with electrons in order to convert them into highly energetic positively charged ions, called molecular ions. The molecular ions may undergo further breakup into smaller ions, called fragment ions.

The molecular ions and the fragment ions are separated by deflection in a variable magnetic field according to their mass to charge ratio (m/e).

The formula to calculate the molecular mass of a compound is,

Molecular mass=[(numer of atoms of the element)(atomic mass of the element)] (1)

Expert Solution & Answer
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Answer to Problem 2.137P

The all possible molecular and fragment ions formed during the mass spectrometry of the compound BF3 with different isotopic compositions are, 10B19F3, 10B19F2, 10B19F, 10B, 11B19F3, 11B19F2, 11B19F and 11B.

The masses of the ions in amu are 67, 48, 29, 10, 68, 49, 30 and 11 respectively.

Explanation of Solution

The two naturally occuring isotopes of the element boron are 10B and 11B. The element fluorine has only one naturally occuring isotope, 19F.

Therefore the molecular and fragment ions for the compound BF3 with different isotopic compositions formed during the mass spectrometry are 10B19F3, 10B19F2, 10B19F, 10B, 11B19F3, 11B19F2, 11B19F and 11B.

The formula to calculate the molecular mass of 10B19F3 is,

Molecular mass=(1)(atomic mass of 10B)+(3)(atomic mass of 19F) (2)

Substitute 10 amu for the atomic mass of 10B and 19 amu for the atomic mass of 19F in equation (2).

Molecular mass=(1)(10 amu)+(3)(19 amu)=10 amu+57 amu=67 amu

The formula to calculate the molecular mass of 10B19F2 is,

Molecular mass=(1)(atomic mass of 10B)+(2)(atomic mass of 19F) (3)

Substitute 10 amu for the atomic mass of 10B and 19 amu for the atomic mass of 19F in equation (3).

Molecular mass=(1)(10 amu)+(2)(19 amu)=10 amu+38 amu=48 amu

The formula to calculate the molecular mass of 10B19F is,

Molecular mass=(1)(atomic mass of 10B)+(1)(atomic mass of 19F) (4)

Substitute 10 amu for the atomic mass of 10B and 19 amu for the atomic mass of 19F in equation (4).

Molecular mass=(1)(10 amu)+(1)(19 amu)=10 amu+19 amu=29 amu

The formula to calculate the molecular mass of 11B19F3 is,

Molecular mass=(1)(atomic mass of 11B)+(3)(atomic mass of 19F) (5)

Substitute 11 amu for the atomic mass of 11B and 19 amu for the atomic mass of 19F in equation (5).

Molecular mass=(1)(11 amu)+(3)(19 amu)=11 amu+57 amu=68 amu

The formula to calculate the molecular mass of 11B19F2 is,

Molecular mass=(1)(atomic mass of 11B)+(2)(atomic mass of 19F) (6)

Substitute 11 amu for the atomic mass of 11B and 19 amu for the atomic mass of 19F in equation (6).

Molecular mass=(1)(11 amu)+(2)(19 amu)=11 amu+38 amu=49 amu

The formula to calculate the molecular mass of 11B19F is,

Molecular mass=(1)(atomic mass of 11B)+(1)(atomic mass of 19F) (7)

Substitute 11 amu for the atomic mass of 11B and 19 amu for the atomic mass of 19F in equation (7).

Molecular mass=(1)(11 amu)+(1)(19 amu)=11 amu+19 amu=30 amu

The masses of ions 10B and 11B are, 10 amu and 11 amu respectively.

Conclusion

The all possible molecular and fragment ions formed during the mass spectrometry of the compound BF3 with different isotopic compositions are, 10B19F3, 10B19F2, 10B19F, 10B, 11B19F3, 11B19F2, 11B19F and 11B.

The masses of the ions in amu are 67, 48, 29, 10, 68, 49, 30 and 11 respectively.

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Chapter 2 Solutions

Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change

Ch. 2.5 - Prob. B2.1PCh. 2.5 - Prob. B2.2PCh. 2.6 - Prob. 2.6AFPCh. 2.6 - Prob. 2.6BFPCh. 2.7 - Prob. 2.7AFPCh. 2.7 - Prob. 2.7BFPCh. 2.8 - Prob. 2.8AFPCh. 2.8 - Prob. 2.8BFPCh. 2.8 - Prob. 2.9AFPCh. 2.8 - Prob. 2.9BFPCh. 2.8 - Prob. 2.10AFPCh. 2.8 - Prob. 2.10BFPCh. 2.8 - Prob. 2.11AFPCh. 2.8 - Prob. 2.11BFPCh. 2.8 - Prob. 2.12AFPCh. 2.8 - Prob. 2.12BFPCh. 2.8 - Prob. 2.13AFPCh. 2.8 - Prob. 2.13BFPCh. 2.8 - Prob. 2.14AFPCh. 2.8 - Prob. 2.14BFPCh. 2.8 - Prob. 2.15AFPCh. 2.8 - Prob. 2.15BFPCh. 2.8 - Prob. 2.16AFPCh. 2.8 - Prob. 2.16BFPCh. 2.8 - Determine the name, formula, and molecular (or...Ch. 2.8 - Prob. 2.17BFPCh. 2.9 - Prob. B2.3PCh. 2 - Prob. 2.1PCh. 2 - List two differences between a compound and a...Ch. 2 - Which of the following are pure substances?...Ch. 2 - Classify each substance in Problem 2.3 as an...Ch. 2 - Explain the following statement: The smallest...Ch. 2 - Prob. 2.6PCh. 2 - Can the relative amounts of the components of a...Ch. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - In our modern view of matter and energy, is the...Ch. 2 - Prob. 2.14PCh. 2 - Which of the following scenes illustrate(s) the...Ch. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Fluorite, a mineral of calcium, is a compound of...Ch. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Dolomite is a carbonate of magnesium and calcium....Ch. 2 - Prob. 2.29PCh. 2 - Which of Dalton’s postulates about atoms are...Ch. 2 - Use Dalton’s theory to explain why potassium...Ch. 2 - Prob. 2.32PCh. 2 - The following charges on individual oil droplets...Ch. 2 - Prob. 2.34PCh. 2 - When Rutherford’s coworkers bombarded gold foil...Ch. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Write the notation for each atomic depiction: Ch. 2 - Write the notation for each atomic depiction: Ch. 2 - Draw atomic depictions similar to those in Problem...Ch. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Chlorine has two naturally occurring isotopes,...Ch. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - What monatomic ions would you expect radium (Z =...Ch. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - The radii of the sodium and potassium ions are 102...Ch. 2 - Prob. 2.77PCh. 2 - What information about the relative numbers of...Ch. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - What is the difference between a homogeneous and a...Ch. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. 2.116PCh. 2 - Which separation method is operating in each of...Ch. 2 - Prob. 2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Ammonium dihydrogen phosphate, formed from the...Ch. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. 2.127PCh. 2 - Prob. 2.128PCh. 2 - The following scenes represent a mixture of two...Ch. 2 - Prob. 2.130PCh. 2 - Prob. 2.131PCh. 2 - Prob. 2.132PCh. 2 - Prob. 2.133PCh. 2 - Prob. 2.134PCh. 2 - Prob. 2.135PCh. 2 - Prob. 2.136PCh. 2 - Prob. 2.137PCh. 2 - Prob. 2.138PCh. 2 - Prob. 2.139PCh. 2 - Prob. 2.140PCh. 2 - Prob. 2.141PCh. 2 - Prob. 2.142PCh. 2 - Prob. 2.143PCh. 2 - Prob. 2.144P
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