EBK PRINCIPLES OF FOUNDATION ENGINEERIN
8th Edition
ISBN: 8220100547058
Author: Das
Publisher: CENGAGE L
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Chapter 2, Problem 2.21P
To determine
Calculate the shear stress parameters
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A consolidated-drained triaxial test on a sand yields the results:All-around confining pressure = σ3 = 30 lb/in2Added axial stress at failure = Δσ = 96 lb/in2Determine the shear stress parameters (i.e., Φ' and c')
In a drained triaxial test on consolidated clay the stress and angle are as follows :
Deviator stress is 20 lb/in2 and friction angle 210 . calculate the effective confining pressure at failure.?
For a normally consolidated clay, these are the results of a drained triaxial test: confining pressure = 112 kPa deviator stress at failure = 175 kPaa) Find the angle of internal friction, ø’.b) Determine the angle θ that the failure plane makes with the major principal plane.c) Find the normal stress σ’ and the shear stress τf on the failure plane.d) Determine the effective normal stress on the plane of maximum shear stress.
Chapter 2 Solutions
EBK PRINCIPLES OF FOUNDATION ENGINEERIN
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- The stresses on a failure plane in a drained triaxial test on sand are as Follows: Normal Stress nf = 100 kN/m2 Shear Stress τf = 40 kN/m2 Required: a) Determine the angle of internal friction and angle of failure plane b) Find the major and minor principle stresses (1 , 3 )arrow_forwardA consolidated-drained triaxial test was conducted on a normally consolidated clay with a chamber pressure, σ3 = 276 kN/m2. The deviator stress at failure is = 276 kN/m2. Determine: a. The angle of friction b. The angle θ that the failure plane makes with the major principal plane c. The normal stress, σf, and the shear stress, τf, on the failure planearrow_forwardA consolidated-drained triaxial test was conducted on a normally consolidated clay.The results were as follows:σ3 = 276 kN/m2(Δσd)f = 276 kN/m2a. Find the angle of friction. ϕ'.b. What is the angle that the failure plane makes with the major principal stress?c. C. Determine the normal stress σ' and the shear stress τf on the failure plane.arrow_forward
- Consolidation of an undrained clay occurs at an effective pressure of 100 kPa and a shear stress of 40 kPa. The ratio of effective pressure to shear stress in drained clay is 2 to 1. If the shear stress at zero effective pressure, To, is 10 kPa, what is the pore water pressure at failure? A. 10 kPa в. 40 кра с. 53 кра D. 67 kPaarrow_forwardA triaxial test conducted on cohesionless soil gives the following results: Deviator stress at failure = 410kPa The angle of shearing resistance = 32 degrees Determine the following: a. Confining pressure in kPa b. Shear stress at failure plane in kPa c. Angle that the failure plane makes with the principal plane (degrees)arrow_forwardThe results of a consolidated drained triaxial shear test on a normally consolidated clay are shown in the figure. The angle of internal friction is:--arrow_forward
- There is an upward flow of 0.06 ml/s through a sand sample with a coefficient of permeability 3 × 10^–2 mm/s. The thickness of the sample is 150 mm and the cross-sectional area is 4500 mm2.Determine the effective stress in N/m2 at the middle of the sample, if the saturated unit weight of the sample, is 18.9 kN/m3.arrow_forwardProblem # 5. The angle of friction of compacted dry sand is 37°. In a direct shear test on the sand, normal stress of 150 kN/m^2 was applied. The size of the specimen was 50mm x 50mm 30 mm (height): a. Compute the shearing stress.b. What shear force will cause will cause shear failure?c. Determine the shear stress at a depth 3m. If the void ratio of the soil is 0.60. Sp. Gr. of sand is 2.70.arrow_forwardSolve it quick? Triaxial test (CU) is performed on a clay for a confining pressure of 110 kPa. If the deviator stress and pore-water pressure were 70 kpa and 55 kpa respectively then determine the internal friction angle.arrow_forward
- In a triaxial test, a specimen of saturated [normally consolidated] clay was consolidated under a chamber confining pressure of 80 kPa. The axial stress on the specimen was then increased through the allowing the drainage from the specimen. The specimen fails when 120 kPa. The pore water pressure at the time was 50 kPa. What is the consolidated undrained friction angle [phi]?arrow_forwardA consolidated drained triaxial is conducted on a normally consolidated soil with chamber confining pressure of 152kPa. If the deviator stress failure is 250kPa, determine the following: a. Calculate the angle of friction of the soil (degrees) b. Calculate the shear stress at the failure plane (kPa) c. Calculate the normal stress at the failure plane (kPa)arrow_forwardThe effective internal friction angle of a normal compacted clay is 33°, the triaxial test of this clay specimen is carried out, and the applied confining pressure is 115 kN/m2. (1) If the compaction undrained test is carried out, the axial differential stress at failure is 102 kN/m2, and the water pressure in the clay test body at failure is determined. (2) If the compaction drainage test is carried out, the applied confining pressure is still 115 kN/m2, and the axial difference stress at the time of failure is determined.arrow_forward
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