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Convert the following instantaneous currents to phasors, using
(a)
(b)
(c)
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- The following is given for a series R-L-C circuit: resistor (R) = 8 Ohms, an inductor (L) = 32 mH and a capacitor (C) = 800uF. The circuit is supplied by a voltage source of e = 120 sin (125t) Volts. What is the angular frequency of the ac source? What is the period of ac source? What is the circuit impedance? What is the power factor? What is the real power of the circuit? What is the rms value of the circuit current?arrow_forwardSolve the following for ALL circuits. Show the summary of your answers at the end of each problem. All answers should be in polar form! a. Total Current b. Individual Currents c. Individual Voltages d. True/Real power e. Reactive power f. Apparent power 1. Circuit 1 (freq=200 Hz) 10 K www 10 COSwt 100 100 LA HE 10 pFarrow_forwardR = 470 L₁ = 47 mH www 000 ZT voo L₂ = 200 mH (c) For the circuit above, the time domain form of the voltage waveform is v(t) = 22 V sin(6161t). determine the total impedance ZT and the determine the total current IT. (Current units are in milliamperes not amperes. Include leading zeros. (example: 0.312A) Do not shift the angles.) Q+j ZT= IF mAz C = 0.1 μF Ωarrow_forward
- b) Find the time varying cos function for the following phasors that have angular frequency of co: i) +1+12√√3 6/60° √12+12 , ii) 2 1+i√√3arrow_forwardThe following is given for a series R-L-C circuit: resistor (R) = 8 Ohms, an inductor (L) = 32 mH and a capacitor (C) = 800uF. The circuit is supplied by a voltage source of e = 120 sin (125t) Volts. What is the angular frequency of the ac source? What is the circuit impedance? What is the power factor? What is the real power of the circuit?arrow_forwardPlot the sinusoid for t=0 to T, where A = 150 mA, f= 35 Hz and 0 = -30°: i(t) = A sin (wt + 0)arrow_forward
- Find the phasor representation of an independent sinusoidal current source given as follows: i(t) = 3cos(300t + 30) + 5sin (100t + 60) A 3230 + 5260 B 3430 + 52 – 30 8430 Cannot be represented as a phasor E None of the abovearrow_forwardTransform the following sinusoidal currents into their amplitude phasor domain:a) i1(t) = 10sin(8t +75o) Ab) i2(t) = −17cos(9t −25o) A (hint: standard cosine form must have a positive amplitude)arrow_forwardTransform the sinusoids corresponding to phasors : (i) V = 50Z- 50° V (ii) V = – 204110 V (iii) I = j(10+ j 5) Aarrow_forward
- A Q1) Convert the following sinusoids to phasors in polar and rectangular form: u(t) = 20 cos(150r–60") V i(e) = -4 cos 3t + 3 cos(3¢–90°) Aarrow_forwardThe phasor of the impedance of an AC circuit has no vertical component. What does this mean? there are no reactive components in the AC circuit the resistance of the circuit is equal to the reactance of the reactive components the inductive reactance and capacitive reactance are equal in magnitude there are no inductors in the circuitarrow_forwardtermining the impedance and current of the system, the voltage across the resistor, and the voltage across the inductor. Could you please forward the response as a print of a handwritten answer? I got these two answers earlier. Which of them would be correct Impedance Z= (1000 + j 90.836) ohm Current I= 0.219∠-5.19° A Voltage across resistor VR = 219.097∠-5.19° V Voltage across inductor VL = 165.195∠84.81° V Impedance will be Z= 1004.052 ∠ 5.12° Current will be i = 0.221 ∠ -5.19° A. Volatge across resistor will be VR = 211.9∠ -5.19° V Volatge across inductor will be VL = 165.12 ∠ 84.81°Varrow_forward
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