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Concept explainers
A three-phase line with an impedance of
Load 1: Absorbs a total of 150 kW and 120 kvar.
Load 2: Delta connected with an impedance of
Load 3: 120 kVA at 0.6 PF leading.
If the line-to-neutral voltage at the load end of the line is 2000 v (rms), determine the magnitude of the line-to-line voltage at the source end of the line.
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Chapter 2 Solutions
MindTap Engineering, 1 term (6 months) Printed Access Card for Glover/Overbye/Sarma's Power System Analysis and Design, 6th
- In a balanced system, the phasor sum of the line-to-line voltages and the phasor sum of the line-to-neutral voltages are always equal to zero. (a) False (b) Truearrow_forwardTwo balanced Y-connected loads, one drawing 10 kW at 0.8 power factor lagging and the other IS kW at 0.9 power factor leading, are connected in parallel and supplied by a balanced three-phase Y-connected, 480-V source. (a) Determine the source current. (b) If the load neutrals are connected to the source neutral by a zero-ohm neutral wire through an ammeter, what will the ammeter read?arrow_forwardThree single-phase transformers, each rated 10MVA,66.4/12.5kV,60Hz, with an equivalent series reactance of 0.1 per unit divided equally between primary and secondary, are connected in a three-phase bank. The high-voltage windings are V-connected and their terminals are directly connected to a 115-kV three-phase bus. The secondary terminals are all shorted together. Find the currents entering the high-voltage terminals and leaving the low-voltage terminals if the low-voltage windings are (a) Y-connected and (b) - connected.arrow_forward
- Figure 3.32 shows the oneline diagram of a three-phase power system. By selecting a common base of 100 MVA and 22 kV on the generator side, draw an impedance diagram showing all impedances including the load impedance in per-unit. The data are given a follows: G:90MVA22kVx=0.18perunitT1:50MVA22/220kVx=0.10perunitT2:40MVA220/11kVx=0.06perunitT3:40MVA22/110kVx=0.064perunitT4:40MVA110/11kVx=0.08perunitM:66.5MVA10.45kVx=0.185perunit Lines I and 2 have series reactances of 48.4 and 65.43, respectively. At bus 4, the three-phase load absorbs 57 MVA at 10.45 kV and 0.6 power factor lagging.arrow_forwardThe Figure shows a balanced Y-A 3Ø circuit. The phase voltages of the Y-connected source are V, = 11020°, V, = 1102 - 120° and V. = 1102120°, Volts. The line impdedances are Z,=10+j5 Q each. The impedances of the A-connected load are ZA = 75+j255 N each. Determine: Line Currents, Phase Currents (load), Power drawn by the load. Ve ZA Vbarrow_forwardIn the circuit in the figure; L1 load draws 15 kVA with lagging power factor 0.6. The L2 load draws 6 kVA with a leading power factor of 0.8. According to this; What is the value of the complex power for the L2 load?arrow_forward
- The one-line diagram of a three-phase power system is shown in the above figure. The line impedances are in per- unit on a 100-MVA base, and the line admittances are neglected. ' qu V = 1.05200 0.01+ j0.025 300 + j200 MVA 3 0.015 + j0.035 150 MW 200 + j150 MVA 0.01 + j0.03 |V = 1.03 The admittance matrix (Y_bus)? The bus power in per-unit?arrow_forwardDraw Wye- Delta three phase transformers connection ( no-load and full-load) in Lt-spicearrow_forwardThe plant capacity of a 3-phase generating station consists of two 8 MVA generators of reactance 14·5%each and one 4 MVA generator of reactance 9·5%. These are connected to a common bus-bar fromwhich loads are taken through a number of 3 MVA step-up transformers each having 4% reactance.Determine the MVA rating of the circuit breakers on (i) L.V. side and (ii) H.V. side. Reactances givenare based on the MVA of each equipment. [(i) 15·24 MVA (ii) 50·25 MVA]arrow_forward
- A Y-connected balanced three-phase source is connected to a three-phase balanced load through a four-wire three-phase cable. The generator has an impedance of 0.1+j0.3 Q/phase. Each phase of the cable has an impedance of 2+2j 2 The phase "B" load voltage is 102-140° kV. The impedance of each phase of the Y-connected load is 3-j5 Q/phase. For a negative sequence: 1- tto pointe) Calculate "terminal" phase voltage of phases "a" and "c" of generator. 2- E points] Calculate Vab and Vca across the load. 5 points Calculate three phase power supplied by the source. 4- 10 point] Calculate three phase power losses.arrow_forwardA balanced three-phase Y-connected source with positive sequance has an internal voltage of 120 V/phase. The source feeds a balanced three-phase Y-connected load having an impedance of 39 + j28 N /phase. The impedance of the transmission line connecting the source to the load is 1+ j20/phase. The a- phase of the source is the reference voltage. a) Draw the equivalent per-phase-circuit for the phase "a". b) Calculate the three line currents in the transmission lines. c) Calculate the three phase voltages at load. d) Calculate the three line-to-line voltages at the terminals of the load. e) Calculate the total average power in watts delivered to the load. f) Calculate the total complex power in VA delivered by the source.arrow_forwardA three-phase system has balanced conditions so that the per-phase circuit representation can be used as shown in Figure 1 Select the turns ratio of the step-up and step-down transformers that the system operates with an efficiency greater than 99 percent. Moreover, find the complex power (received or given) of all components in the circuit and the V1 and V2 voltages. The load voltage is specified as 4 kV rms, and the load impedance is 4/3 ohm. ..arrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning
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