PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
2nd Edition
ISBN: 9781266811852
Author: SMITH
Publisher: MCG
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Chapter 2, Problem 2.61AP

(a)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in 1327Al has to be given.

Concept introduction;

Atomic number (Z):

Atomic number of an element is the number of protons found in the nucleus of every atom of that element.

Mass number (A):

Mass number of an element is defined as the total number of protons and neutrons in an atom.

Protons:

A proton is one of three main particles that make up the atom.  Protons are a tiny, dense region at the center of the atom.  Protons have a positive electrical charge of +1 and a mass of 1 atomic mass which is 1.62×10-27 kilograms.

Neutrons:

Atoms of all elements except for most atoms of hydrogen have neutrons in their nucleus. Unlike protons and electrons, which are electrically charged, neutrons have no charge they are electrically neutral.

Electrons:

Electrons have an electric charge of -1, which is equal but opposite to the charge of a proton, which have an electric charge of +1.  All atoms have the same number of electrons as protons, so the positive and negative charges cancel out making atoms electrically neutral.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number is 13.

The mass number is 27.

The number of proton is,

  Atomic number of an element=Number of protons

Thus, the number of protons in the atom is 13.

The number of electrons is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 13.

The number of neutrons can be calculated as,

  A=Numberofprotons+Numberofneutrons

  Numberofneutrons=A-NumberofprotonsNumberofneutrons=27-13Numberofneutrons=14

The number of neutrons in an atom is 14.

(b)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in 1735Cl has to be given.

Concept introduction;

Refer to part (a).

(b)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number is 17.

The mass number is 35.

The number of proton is,

  Atomic number of an element=Number of protons

Thus, the number of protons in the atom is 17.

The number of electron is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 17.

The number of neutrons can be calculated as,

  A=Numberofprotons+Numberofneutrons

  Numberofneutrons=A-NumberofprotonsNumberofneutrons=35-17Numberofneutrons=18

The number of neutrons in an atom is 18.

(c)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in 1634S has to be given.

Concept introduction;

Refer to part (a).

(c)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number is 16.

The mass number is 34.

The number of proton is,

  Atomic number of an element=Number of protons

Thus, the number of protons in the atom is 16.

The number of electron is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 16.

The number of neutrons can be calculated as,

  A=Numberofprotons+Numberofneutrons

  Numberofneutrons=A-NumberofprotonsNumberofneutrons=34-16Numberofneutrons=18

The number of neutrons in an atom is 18.

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Chapter 2 Solutions

PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.

Ch. 2.2 - Prob. 2.11PCh. 2.2 - Prob. 2.12PCh. 2.2 - Prob. 2.13PCh. 2.3 - Prob. 2.14PCh. 2.3 - Prob. 2.15PCh. 2.3 - Prob. 2.16PCh. 2.3 - Prob. 2.17PCh. 2.3 - Prob. 2.18PCh. 2.4 - Prob. 2.19PCh. 2.4 - Give the period and group number for each element:...Ch. 2.4 - Prob. 2.21PCh. 2.4 - Prob. 2.22PCh. 2.5 - Prob. 2.23PCh. 2.6 - Prob. 2.24PCh. 2.6 - Prob. 2.25PCh. 2.6 - Prob. 2.26PCh. 2.7 - Identify the total number of electrons, the number...Ch. 2.7 - Prob. 2.28PCh. 2.7 - Prob. 2.29PCh. 2.8 - Which element in each pair has the larger atomic...Ch. 2.8 - Which element in each pair has the higher...Ch. 2.8 - Prob. 2.32PCh. 2 - Identify the elements used in each example of...Ch. 2 - Prob. 2.34UKCCh. 2 - Prob. 2.35UKCCh. 2 - Prob. 2.36UKCCh. 2 - Prob. 2.37UKCCh. 2 - Prob. 2.38UKCCh. 2 - Prob. 2.39UKCCh. 2 - Prob. 2.40UKCCh. 2 - Prob. 2.41UKCCh. 2 - Prob. 2.42UKCCh. 2 - Prob. 2.43UKCCh. 2 - Prob. 2.44UKCCh. 2 - Prob. 2.45APCh. 2 - Prob. 2.46APCh. 2 - Prob. 2.47APCh. 2 - Identify the elements in each chemical formula and...Ch. 2 - Prob. 2.49APCh. 2 - Prob. 2.50APCh. 2 - Prob. 2.51APCh. 2 - Prob. 2.52APCh. 2 - Prob. 2.53APCh. 2 - Prob. 2.54APCh. 2 - Prob. 2.55APCh. 2 - Prob. 2.56APCh. 2 - Prob. 2.57APCh. 2 - Prob. 2.58APCh. 2 - The most common isotope of oxygen has a mass...Ch. 2 - Prob. 2.60APCh. 2 - Prob. 2.61APCh. 2 - Prob. 2.62APCh. 2 - Prob. 2.63APCh. 2 - Prob. 2.64APCh. 2 - Prob. 2.65APCh. 2 - Prob. 2.66APCh. 2 - Prob. 2.67APCh. 2 - Prob. 2.68APCh. 2 - Prob. 2.69APCh. 2 - Prob. 2.70APCh. 2 - Prob. 2.71APCh. 2 - Prob. 2.72APCh. 2 - Prob. 2.73APCh. 2 - Prob. 2.74APCh. 2 - Prob. 2.75APCh. 2 - Prob. 2.76APCh. 2 - Prob. 2.77APCh. 2 - Prob. 2.78APCh. 2 - Prob. 2.79APCh. 2 - Prob. 2.80APCh. 2 - Prob. 2.81APCh. 2 - Prob. 2.82APCh. 2 - Prob. 2.83APCh. 2 - Arrange the elements in each group in order of...Ch. 2 - Prob. 2.85APCh. 2 - Prob. 2.86APCh. 2 - Answer the following questions about...Ch. 2 - Prob. 2.88APCh. 2 - Prob. 2.89APCh. 2 - (a) What is the chemical formula for...Ch. 2 - Prob. 2.91CPCh. 2 - Prob. 2.93BTCCh. 2 - Prob. 2.95BTC
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