PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
2nd Edition
ISBN: 9781266811852
Author: SMITH
Publisher: MCG
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 2, Problem 2.62AP

(a)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in Silver-115 has to be given.

Concept introduction;

Atomic number (Z):

Atomic number of an element is the number of protons found in the nucleus of every atom of that element.

Mass number (A):

Mass number of an element is defined as the total number of protons and neutrons in an atom.

Protons:

A proton is one of three main particles that make up the atom.  Protons are a tiny, dense region at the center of the atom.  Protons have a positive electrical charge of +1 and a mass of 1 atomic mass which is 1.62×10-27 kilograms.

Neutrons:

Atoms of all elements except for most atoms of hydrogen have neutrons in their nucleus. Unlike protons and electrons, which are electrically charged, neutrons have no charge they are electrically neutral.

Electrons:

Electrons have an electric charge of -1, which is equal but opposite to the charge of a proton, which have an electric charge of +1.  All atoms have the same number of electrons as protons, so the positive and negative charges cancel out making atoms electrically neutral.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given,

The mass number of silver is 115.

The atomic number of silver is 47.

The number of proton is,

  Atomic number of an element=Number of protons

Thus, the number of protons in the atom is 47.

The number of electrons is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 47.

The number of neutrons can be calculated as,

  A = Numberofprotons+Numberofneutrons

  Numberofneutrons = A-NumberofprotonsNumberofneutrons = 115-47Numberofneutrons = 68

The number of neutrons in an atom is 68.

(b)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in Gold-197 has to be given.

Concept introduction;

Refer to part (a).

(b)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number of gold is 79.

The mass number of gold is 197.

The number of proton is,

  Atomic number of an element = Number of protons

Thus, the number of protons in the atom is 79.

The number of electron is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 79.

The number of neutrons can be calculated as,

  A = Numberofprotons+Numberofneutrons

  Numberofneutrons = A-NumberofprotonsNumberofneutrons = 197-79Numberofneutrons = 118

The number of neutrons in an atom is 118.

(c)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in Radon-222 has to be given.

Concept introduction;

Refer to part (a).

(c)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number of radon is 86.

The mass number of radon is 222.

The number of proton is,

  Atomic number of an element = Number of protons

Thus, the number of protons in the atom is 86.

The number of electron is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 86.

The number of neutrons can be calculated as,

  A=Numberofprotons+Numberofneutrons

  Numberofneutrons=A-NumberofprotonsNumberofneutrons=222-86Numberofneutrons=136

The number of neutrons in an atom is 136.

(d)

Interpretation Introduction

Interpretation:

The number of protons, the number of neutrons and the number of electrons in osmium,-192 has to be given.

Concept introduction;

Refer to part (a).

(d)

Expert Solution
Check Mark

Explanation of Solution

Given,

The atomic number of radon is 76.

The mass number of radon is 192.

The number of proton is,

  Atomic number of an element=Number of protons

Thus, the number of protons in the atom is 76.

The number of electron is,

  Numberofelectrons=NumberofProtons

Thus, the number of electrons in the atom is 76.

The number of neutrons can be calculated as,

  A = Numberofprotons+Numberofneutrons

  Numberofneutrons = A-NumberofprotonsNumberofneutrons = 192-76Numberofneutrons = 116

The number of neutrons in an atom is 116.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 2 Solutions

PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.

Ch. 2.2 - Prob. 2.11PCh. 2.2 - Prob. 2.12PCh. 2.2 - Prob. 2.13PCh. 2.3 - Prob. 2.14PCh. 2.3 - Prob. 2.15PCh. 2.3 - Prob. 2.16PCh. 2.3 - Prob. 2.17PCh. 2.3 - Prob. 2.18PCh. 2.4 - Prob. 2.19PCh. 2.4 - Give the period and group number for each element:...Ch. 2.4 - Prob. 2.21PCh. 2.4 - Prob. 2.22PCh. 2.5 - Prob. 2.23PCh. 2.6 - Prob. 2.24PCh. 2.6 - Prob. 2.25PCh. 2.6 - Prob. 2.26PCh. 2.7 - Identify the total number of electrons, the number...Ch. 2.7 - Prob. 2.28PCh. 2.7 - Prob. 2.29PCh. 2.8 - Which element in each pair has the larger atomic...Ch. 2.8 - Which element in each pair has the higher...Ch. 2.8 - Prob. 2.32PCh. 2 - Identify the elements used in each example of...Ch. 2 - Prob. 2.34UKCCh. 2 - Prob. 2.35UKCCh. 2 - Prob. 2.36UKCCh. 2 - Prob. 2.37UKCCh. 2 - Prob. 2.38UKCCh. 2 - Prob. 2.39UKCCh. 2 - Prob. 2.40UKCCh. 2 - Prob. 2.41UKCCh. 2 - Prob. 2.42UKCCh. 2 - Prob. 2.43UKCCh. 2 - Prob. 2.44UKCCh. 2 - Prob. 2.45APCh. 2 - Prob. 2.46APCh. 2 - Prob. 2.47APCh. 2 - Identify the elements in each chemical formula and...Ch. 2 - Prob. 2.49APCh. 2 - Prob. 2.50APCh. 2 - Prob. 2.51APCh. 2 - Prob. 2.52APCh. 2 - Prob. 2.53APCh. 2 - Prob. 2.54APCh. 2 - Prob. 2.55APCh. 2 - Prob. 2.56APCh. 2 - Prob. 2.57APCh. 2 - Prob. 2.58APCh. 2 - The most common isotope of oxygen has a mass...Ch. 2 - Prob. 2.60APCh. 2 - Prob. 2.61APCh. 2 - Prob. 2.62APCh. 2 - Prob. 2.63APCh. 2 - Prob. 2.64APCh. 2 - Prob. 2.65APCh. 2 - Prob. 2.66APCh. 2 - Prob. 2.67APCh. 2 - Prob. 2.68APCh. 2 - Prob. 2.69APCh. 2 - Prob. 2.70APCh. 2 - Prob. 2.71APCh. 2 - Prob. 2.72APCh. 2 - Prob. 2.73APCh. 2 - Prob. 2.74APCh. 2 - Prob. 2.75APCh. 2 - Prob. 2.76APCh. 2 - Prob. 2.77APCh. 2 - Prob. 2.78APCh. 2 - Prob. 2.79APCh. 2 - Prob. 2.80APCh. 2 - Prob. 2.81APCh. 2 - Prob. 2.82APCh. 2 - Prob. 2.83APCh. 2 - Arrange the elements in each group in order of...Ch. 2 - Prob. 2.85APCh. 2 - Prob. 2.86APCh. 2 - Answer the following questions about...Ch. 2 - Prob. 2.88APCh. 2 - Prob. 2.89APCh. 2 - (a) What is the chemical formula for...Ch. 2 - Prob. 2.91CPCh. 2 - Prob. 2.93BTCCh. 2 - Prob. 2.95BTC
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Chemistry In Focus
Chemistry
ISBN:9781337399692
Author:Tro, Nivaldo J.
Publisher:Cengage Learning,
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
NEET Chemistry | Group 14 Carbon Family | Theory & Problem Solving | In English | Misostudy; Author: Misostudy;https://www.youtube.com/watch?v=enOGIrcHh54;License: Standard YouTube License, CC-BY