Chapter 2, Problem 2.67HW

You are given the task of writing a procedure int_size_is_32() that yields 1 when run on a machine for which an into is 32 bits and yields 0 otherwise. You are not allowed to use the size of operator. Here is a first attempt:

When compiled and run on a 32-bit SUN SPARC, however, this procedure returns 0. The following compiler message gives us an indication of the problem:

Warning: left shift count >= width of type

1. A.    In what way does our code fail to comply with the C standard?
2. B. Modify the code to run properly on any machine for which data type int is at least 32 bits.
3. C. Modify the code to run properly on any machine for which data type int is at least 16 bits.