Chapter 2.4, Problem 2.46PP

A.

Explanation of Solution

Calculation of binary representation:

• From the given question, the binary value of “1/10” is represented by “0.000110011[0011]…….₂”.
  • The portion of given brackets denotes the value “0011” repeated indefinitely.
  • Consider the value of “0.1” is first “23” bits of the sequence of the binary points.
    • That is “23” bits from “0.000110011[0011]…….₂” is “0.00011001100110011001100”.
    • It is assumed as the “x” value.
• Now computing the value of “0.1 – x” is shown below:
  • The binary value of “0.1” is “0.00011001100110011001100”.
  • The binary value of “x” is “0.00011001100110011001100”.
  • Determining the value of “0.1 – x” means.
    • The value of “x” is in negative. So, need to take 2’s complement

      Binary value of “x”: 0.00011001100110011001100

      1’s complement: 1...

B.

Explanation of Solution

Calculation of decimal representation:

• From the given question, the binary value of “1/10” is represented by “0.000110011[0011]…….₂”.
  • The portion of given brackets denotes the value “0011” repeated indefinitely.
  • Consider the value of “0.1” is first “23” bits of the sequence of the binary points.
    • That is “23” bits from “0.000110011[0011]…….₂” is “0.00011001100110011001100”.
    • It is assumed as the “x” value...

C.

Explanation of Solution

Time calculation of difference between the actual time and the time computed by the software:

From the given question, the system had been running for around “100” hours. So, from the part B, the time computed by the software is “$\text{9}\text{.54 }\times {\text{ 10}}^{\text{-8}}\times \text{ 100 hours}$”.

In general, 1 hour = $\text{ 60 }\times \text{ 60}$ seconds. Then $\text{9}\text{.54 }\times {\text{ 10}}^{\text{-8}}\times \text{ 100 }\times \text{ 60}\times \text{60}$

From the given question, the counter is increment at “0

D.

Explanation of Solution

Calculation of prediction:

From the given question, a Scud travels at around 2,000 meters per second.

From the part C, the time is “0.343” seconds...