CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
14th Edition
ISBN: 9781259327933
Author: Burdge
Publisher: MCG
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Chapter 2, Problem 2.73QP

a)

Interpretation Introduction

Interpretation: The ratio of neutrons to protons along with their respective numbers in the nucleus of each atom to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

a)

Expert Solution
Check Mark

Answer to Problem 2.73QP

a. Isotope                            24He      1020Ne       1840Ar       3684Kr        54132Xe.   No.of Protons                     2          10          18          36            54   No.of Neutrons                   2          10          22          48            78

Explanation of Solution

Predict the number of protons and neutrons of each atom.

The element symbol : ZAX,where, A (mass number) = no.of protons + no.of  neutrons.            Z (atomic number) = no. of protons. (electrons = protons).

  • The element symbol : 24He,

Z (atomic number) = no. of protons. (protons = electrons)= 2.No.of  neutrons     = A (mass number)  -  no.of protons                             = 4 -  2 = 2.No.of Protons   :  2No.of neutrons  :  2

In the helium atom, the atomic number 2 is equal to protons number and the differences between the mass number and proton number obtains the neutron number 2.

  • The element symbol : 1020Ne,

Z (atomic number) = no. of protons. (protons = electrons)= 10.No.of  neutrons     = A (mass number)  -  no.of protons                             = 20 -  10 = 10.No.of Protons   :  10No.of neutrons  :  10

In the Neon atom, the atomic number 10 is equal to protons number and the differences between the mass number and proton number obtains the neutron number 10.

  • The element symbol : 1840Ar,

Z (atomic number) = no. of protons. (protons = electrons)= 18.No.of  neutrons     = A (mass number)  -  no.of protons                             = 40 -  18 = 22.No.of Protons   :  18No.of neutrons  :  22

In the Argon atom, the atomic number 18 is equal to protons number and the differences between the mass number and proton number obtains the neutron number 22.

  • The element symbol : 3684Kr,

Z (atomic number) = no. of protons. (protons = electrons)= 36.No.of  neutrons     = A (mass number)  -  no.of protons                             = 84 -  36 = 48.No.of Protons   :  36No.of neutrons  :  48

In the Krypton atom, the atomic number 36 is equal to protons number and the differences between the mass number and proton number obtains the neutron number 48.

  • The element symbol : 54132Xe,

Z (atomic number) = no. of protons. (protons = electrons)= 54.No.of  neutrons     = A (mass number)  -  no.of protons                             = 132 -  54 = 78.No.of Protons   :  54No.of neutrons  :  78

In the Xenon atom, the atomic number 54 is equal to protons number and the differences between the mass number and proton number obtains the neutron number 78.

Conclusion

The ratio of neutrons to protons along with their respective numbers in the nucleus of each atom is identified.

b)

Interpretation Introduction

Interpretation: The ratio of neutrons to protons along with their respective numbers in the nucleus of each atom to be identified.

Concept Introduction:

Conversion of atoms to moles: no.of moles  = no.of atomsAvogadro's number.

Nuclear stability: The nucleus is composed of protons and neutrons. The strongest nuclear force binds the particles tightly. Though the protons repel each other due to no attraction between similar charges, possess short-range attractions made the attraction possible between proton and proton, proton and neutron, neutron and neutron.

The stability of any element is determined by the difference between columbic repulsion and the short-range attraction. If repulsion outweighs the attraction, the disintegration of nucleus occurs by producing the daughter nuclides. If the attractive forces prevail, the nucleus is stable.

b)

Expert Solution
Check Mark

Answer to Problem 2.73QP

b. neutron/proton ratio        1.00       1.00      1.22       1.33          1.44  The ratio increasing with increasing atomic number.

Explanation of Solution

Analyze the ratio of neutrons to protons for each element.

b. Isotope                            24He      1020Ne       1840Ar          3684Kr        54132Xe.   No.of Protons                     2          10          18            36            54   No.of Neutrons                   2          10          22            48            78 Neutron/proton ratio2/2       10/10     22/18       48/36      78/54                                            1.00       1.00        1.22          1.33       1.44 

The ratio of neutron to proton is increasing down the group along with increasing the atomic number.

Conclusion
The ratio of neutrons to protons along with their respective numbers in the nucleus of each atom is identified.

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Chapter 2 Solutions

CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT

Ch. 2.5 - The average atomic mass of nitrogen is 14.0067....Ch. 2.5 - Prob. 2PPCCh. 2.5 - Boron has two naturally occurring isotopes, 10B...Ch. 2.5 - The two naturally occurring isotopes of antimony,...Ch. 2.6 - Prob. 2.6.1SRCh. 2.6 - Prob. 2.6.2SRCh. 2.7 - Calcium is the most abundant metal in the human...Ch. 2.7 - Prob. 3PPACh. 2.7 - Calculate (a) the number of atoms in 1.05 106...Ch. 2.7 - Prob. 3PPCCh. 2.7 - Prob. 2.4WECh. 2.7 - Prob. 4PPACh. 2.7 - Prob. 4PPBCh. 2.7 - Prob. 4PPCCh. 2.7 - Prob. 2.5WECh. 2.7 - Prob. 5PPACh. 2.7 - Prob. 5PPBCh. 2.7 - Prob. 5PPCCh. 2.7 - Prob. 2.7.1SRCh. 2.7 - Prob. 2.7.2SRCh. 2.7 - Prob. 2.7.3SRCh. 2.7 - Prob. 2.7.4SRCh. 2 - Define the terms atom and element.Ch. 2 - Use a familiar macroscopic example as an analogy...Ch. 2 - Prob. 2.3QPCh. 2 - Prob. 2.4QPCh. 2 - Prob. 2.5QPCh. 2 - Prob. 2.6QPCh. 2 - Describe the experimental basis for believing that...Ch. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Determine the mass number of (a) a beryllium atom...Ch. 2 - Prob. 2.21QPCh. 2 - The following radioactive isotopes are used in...Ch. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - What is the mass (in amu) of a carbon-12 atom? Why...Ch. 2 - Prob. 2.32QPCh. 2 - What information would you need to calculate the...Ch. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - The element rubidium has two naturally occurring...Ch. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Give two examples of each of the following: (a)...Ch. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Describe the changes in properties (from metals to...Ch. 2 - Consult the WebElements Periodic Table of the...Ch. 2 - Group the following elements in pairs that you...Ch. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.61QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - The element francium (Fr) was the last element of...Ch. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Discuss the significance of assigning an atomic...Ch. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76QPCh. 2 - Identify each of the following elements: (a) a...Ch. 2 - Prob. 2.78QPCh. 2 - Prob. 2.79QPCh. 2 - Prob. 2.80QPCh. 2 - Prob. 2.81QPCh. 2 - Prob. 2.82QPCh. 2 - Prob. 2.83QPCh. 2 - Prob. 2.84QP
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