(a)
Interpretation:
The number of valence electrons present in
Concept Introduction:
The convention followed to remove or add electrons is electrons of largest principal quantum number are lost first. In case of subshells of the same
(b)
Interpretation:
The number of valence electrons present in
Concept Introduction:
Refer to part (a).
(c)
Interpretation:
The number of valence electrons present in
Concept Introduction:
Refer to part (a).
(d)
Interpretation:
The number of valence electrons present in
Concept Introduction:
Refer to part (a).
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Chapter 2 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
- There is persuasive evidence for the brief existence of the unstable molecule OPCl. (a) Draw a Lewis diagram for this molecule in which the octet rule is satisfied on all atoms and the formal charges on all atoms are zero. (b) The compound OPCl reacts with oxygen to give O2PCl. Draw a Lewis diagram of O2PCl for which all formal charges are equal to zero. Draw a Lewis diagram in which the octet rule is satisfied on all atoms.arrow_forwardCyanogen (CN)2 is known as pseodohalogen because it has some properties like halogens. It is composed of two CN’s joined together.(i) Draw the Lewis structure for all the possible combination for (CN)2.(ii) Calculate the formal charge and determine which one of the structures that you have drawn is most stable.(iii) For the stable structure, determine the geometry around the two central atoms.(iv) For the stable structure, draw the dipole arrows for the bonds.(v) Base on the stable structure, determine the polarity of molecule and state your reason.arrow_forwardGive a reason why each of the following statements is a safeprediction:(a) Every compound of Rb with a nonmetal is ionic in character.(b) Every compound of nitrogen with a halogen element is amolecular compound.(c) The compound MgKr2 does not exist.(d) Na and K are very similar in the compounds they form withnonmetals.(e) If contained in an ionic compound, calcium (Ca) will be inthe form of the doubly charged ion, Ca2arrow_forward
- Define the following phenomena with reference to main group compounds: (d) multicenter electron deficient bondingarrow_forwardiv. Assign formal charges to the atoms in the following structures and decide which the more important contributor to the resonance hybrid is. (a) (b) H H C=N=N c-N=N H H v. What factor accounts for each of the following differences in bond length? (a) I, has a longer bond than Br,. (b) C-N bonds are shorter than C-C bonds. (c) H-C bonds are shorter than the C-O bond. (d) The C-O bond in formaldehyde, H,C=0, is longer than the bond in carbon monoxide, C=0.arrow_forwardWrite the electron configuration for each of the following ions and determine which one possess noble-gas configurations: (a) Sr2+; (b) Ti2+; (c) Se2-; (d) Ni2+; (e) Br-; (f) Mn3+.arrow_forward
- In addition to ammonia, nitrogen forms three other hy-drides: hydrazine (N₂H₄), diazene (N₂H₂), and tetrazene (N₄H₄).(a) Use Lewis structures to compare the strength, length, and or-der of nitrogen-nitrogen bonds in hydrazine, diazene, and N₂.(b) Tetrazene (atom sequence H₂NNNNH₂) decomposes above 0°C to hydrazine and nitrogen gas. Draw a Lewis structure fortetrazene, and calculate ΔH°ᵣₓₙ for this decomposition.arrow_forwardWhich of the following bonds are polar: (a) P—O; (b) S—F; (c) Br—Br; (d) O—Cl? Which is the more electronegative atom in each polar bond?arrow_forward(c) Draw the orbital diagrams and Lewis symbols to depict the formation of Na* and CI ions from the atoms. Give the formula of the compound formed. (d) The predicted bond length for HF is 109 pm (the sum of the covalent radii of H, 37 pm and F. 72 pm), however the actual bond length for HF is shorter (92 pm). It was observed that the difference between predicted and actual bond lengths becomes smalleor going down the halogen group from HF to HI Describe these observationsarrow_forward
- Draw Lewis structures for the following compounds.(a) ammonia, NH3 (b) water, H2O(c) hydronium ion, H3O+ (d) propane, C3H8(e) dimethylamine, CH3NHCH3 (f) diethyl ether, CH3CH2OCH2CH3(g) 1-chloropropane, CH3CH2CH2Cl (h) propane-2-ol, CH3CH(OH)CH3(i) borane, BH3 (j) boron trifluoride, BF3Explain what is unusual about the bonding in the compounds in parts (i) and (j)arrow_forwardConsider the collection of nonmetallic elements O, P, Te,I, and B. (a) Which two would form the most polar singlebond? (b) Which two would form the longest single bond?(c) Which two would be likely to form a compound of formulaXY2? (d) Which combinations of elements would likelyyield a compound of empirical formula X2Y3?arrow_forwardWhich of the following compounds does not contain both ionic and covalent bonding? Justify your answer. (a) Na2SO4(b) NH+NO3(c) NH4C1(d) KCl(e) KclO4arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
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