Fundamentals of Thermal-Fluid Sciences
Fundamentals of Thermal-Fluid Sciences
5th Edition
ISBN: 9780078027680
Author: Yunus A. Cengel Dr., Robert H. Turner, John M. Cimbala
Publisher: McGraw-Hill Education
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Chapter 2, Problem 53P
To determine

The absolute pressure in the pipeline.

Expert Solution & Answer
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Explanation of Solution

Given:

Local atmospheric pressure (Patm) is 14.2psia.

Height of the mercury in the manometer (hHg) is 6in..

Height of the water in the manometer (hH2O) is 27in..

Height of the oil in the manometer (hoil) is 15in..

Density of the water (ρH2O) is 62.4lbm/ft3.

Specific gravity of the mercury (SGHg) is 13.6.

Specific gravity of the oil (SGoil) is 0.69.

Acceleration due to gravity (g) is 32.2ft/s2.

Calculation:

Calculate the density of the mercury (ρHg).

  ρHg=(ρH2O)(SGHg)=(62.4lbm/ft3)(13.6)=848.6lbm/ft3

Calculate the density of the oil (ρoil).

  ρoil=(ρH2O)(SGoil)=(62.4lbm/ft3)(0.69)=43.1lbm/ft3

Calculate the absolute pressure in the pipeline (P1).

  P1ρHgghHg+ρoilghoilρH2OghH2O=Patm

  P1=Patm+ρHgghHg+ρH2OghH2Oρoilghoil={(14.2psia)+(848.6lbm/ft3)(32.2ft/s2)(6in.)+(62.4lbm/ft3)(32.2ft/s2)(27in.)(43.1lbm/ft3)(32.2ft/s2)(15in.)}={(14.2psia)+(848.6lbm/ft3)(32.2ft/s2)(612ft)+(62.4lbm/ft3)(32.2ft/s2)(2712ft)(43.1lbm/ft3)(32.2ft/s2)(1512ft)}=(14.2psia)+(32.2ft/s2)[(424.3lbm/ft2)+(140.4lbm/ft2)(53.875lbm/ft2)]={(14.2psia)+(32.2ft/s2)[(424.3lbm/ft2)+(140.4lbm/ft2)(53.875lbm/ft2)](132.2lbmft/s2)(1ft2144in2)}=17.7psia

Thus, the absolute pressure in the pipeline is 17.7psia_.

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Chapter 2 Solutions

Fundamentals of Thermal-Fluid Sciences

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