Concept explainers
Interpretation:
A structure for A and two possible structures for B are to be proposed based on the given information.
Concept introduction:
Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various
It depends on the interactions of atoms or molecules with the
In IR spectroscopy, the
The
The
Ketone functional group shows absorption band at
The
The higher the ring strain, the higher will be the stretching frequency.
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ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
- Compound B has molecular formula C9H10. The IR spectrum is shown below. The 1H-NMR spectrum shows a multiplet at 7.2 ppm integrating to 4H, a triplet at 2.9 ppm integrating to 4H, and a triplet at 2.1 ppm integrating to 2 H. Suggest a structure for B and explain your reasoningarrow_forwardCompound X has molecular formula C5H10. In the presence of a metal catalyst, compound X reacts with one equivalent of molecular hydrogen to yield 2-methylbutane. (1) Suggest three possible structures for compound X. (2) Hydroboration-oxidation of compound X yields a product with no chirality centers. Identify the structure of compound X.arrow_forward08) The NMR spectra of the two isomeric compounds with formula C3H5ClO2 are shown in letters a and b. Low-field protons appearing in the NMR spectrum around 12.1 and 11.5 ppm, respectively, are shown highlighted. Draw the structures of the isomers.arrow_forward
- The pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?arrow_forwardOrganometallic compounds such as magnesium and lithium are characterized by the C-M bond. Explain in detail why these compounds function as bases, which ends up limiting their application to ethereal reaction conditions.arrow_forwardAcridine is a heterocyclic aromatic compound obtained from coal tar that is used in the synthesis of dyes. The molecular formula of acridine is C13H9N, and its ring system is analogous to that of anthracene except that one CH group has been replaced by N. The two most stable resonance structures of acridine are equivalent to each other, and both contain a pyridine-like structural unit. Write a structural formula for acridine.arrow_forward
- The pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?(c) How many nodes are there in the lowest-energy MO of the pentadienyl system? How many in the highest-energy MO?(d) Draw the MOs of the pentadienyl system in order of increasing energy. (continued)762 CHAPTER 15 Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy(e) Show how many electrons are in each MO for the pentadienyl radical (ground state).(f) Show how your molecular orbital picture agrees with the resonance picture showing delocalization of the unpairedelectron onto three carbon atoms.(g) Remove the highest-energy electron from the pentadienyl radical to give the pentadienyl cation. Which carbon atomsshare the positive charge? Does this picture agree with the resonance picture?(h) Add an…arrow_forwardThe pentadienyl radical, H2C“CH¬CH“CH¬CH2#, has its unpaired electron delocalized over three carbon atoms.(a) Use resonance forms to show which three carbon atoms bear the unpaired electron.(b) How many MOs are there in the molecular orbital picture of the pentadienyl radical?(c) How many nodes are there in the lowest-energy MO of the pentadienyl system? How many in the highest-energy MO?(d) Draw the MOs of the pentadienyl system in order of increasing energyarrow_forwardCompound X (structure shown below) has a molecular formula C5H1o and reacts with H2/Pt to give compound Y, C5H12. What is the name of the reaction involved to produce Compound Y? H2C H3C CH3 Hydration Hydrogenation Halogenation Addition of halohydrinarrow_forward
- Reaction of (CH3)3CH with Cl2 forms two products: (CH3)2CHCH2Cl (63%) and (CH3)3CCl (37%). Why is the major product formed by cleavage of the stronger 1° C–H bond?arrow_forwardCompounds A and B are isomers having molecular formula C5H12. Heating A with Cl2 gives a single product of monohalogenation, whereas heating B under the same conditions forms three constitutional isomers. What are thestructures of A and B?arrow_forwardA compound of unknown structure (Compound A) is determined by elemental analysis to have a molecular formula of C10H12. Upon reaction with H2 and Pd/CacO3 the unknown absorbs one mole equivalent of hydrogen gas. Upon reaction with ozone, followed by zinc/acetic acid a product with structure shown is obtained. Four possibilities are given for the structure of Compound A. Select the correct answer. HO,C B A D В Both B and C are correct O o o o oarrow_forward