Concept explainers
(a)
Time after which the two stones hit each other after the release of first stone.
(a)
Answer to Problem 63AP
The time after which the two stones hit each other after the release of the first stone is
Explanation of Solution
Let
Write the expression for the displacement of the first stone after the release.
Here,
Express equation (I) as a quadratic form.
Write the general expression for a second order quadratic equation.
Write the expression for the solution of expression (III).
Use expression (III) in (IV) and solve for
Conclusion:
Substitute
Compare expression (VII) with the general equation (III) and find the values of constants.
Substitute
Therefore, the time after which the two stones hit each other is
(b)
The initial velocity of the stone if they are hitting each other simultaneously.
(b)
Answer to Problem 63AP
The initial velocity of the stone if they are hitting each other simultaneously is
Explanation of Solution
The two stones are thrown vertically downward and they hit each other in a time interval of
Use expression (I) to find
Conclusion:
Substitute
Therefore, the initial velocity of the stone if they are hitting each other simultaneously is
(c)
Speed of both stones when they hit the water.
(c)
Answer to Problem 63AP
Speed of first stone is
Explanation of Solution
Write the expression for the final velocity of first stone.
Here,
Write the expression for the final velocity of second stone.
Here,
Conclusion:
Substitute
Substitute
Therefore, speed of first stone is
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Chapter 2 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
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