Produce an expected progression Program plan: Declare the header files and namespace. Create a class “Progression”, Define the constructor. Declare the protected access modifier. Declare the pure virtual methods. Declare the necessary protected member variables. Create a class “SqrootProgression” that extends “Progression”, Declare the public member variables. Define the default constructor, Set the first value to “65536”. Initialize the starting variable. Define the parameterized constructor to initialize with the specified value. Define the method “firstValue()” to reset to the first value. Assign the first value to the previous value. Return the previous value. Define the method “nextValue()” to advances the next value. Assign the square root of the previous value to the temporary variable. Update the previous value with the square root. Return the previous value. Define the “main()” method, Create array object for “SqrootProgression”. Print the value returned from the method “firstValue()”. Print the value returned from the method “nextValue()”.

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Answer 1

Question

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

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Answer 2

Question

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

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Answer 3

Question

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

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Answer 4

Question

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

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Answer 5

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

Answer 6

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

Answer 7

Chapter 2, Problem 6C

Program Plan Intro

Produce an expected progression

Program plan:

Declare the header files and namespace.

Create a class “Progression”,

Define the constructor.

Declare the protected access modifier.

Declare the pure virtual methods.

Declare the necessary protected member variables.

Create a class “SqrootProgression” that extends “Progression”,

Declare the public member variables.

Define the default constructor,

Set the first value to “65536”.

Initialize the starting variable.

Define the parameterized constructor to initialize with the specified value.

Define the method “firstValue()” to reset to the first value.

Assign the first value to the previous value.

Return the previous value.

Define the method “nextValue()” to advances the next value.

Assign the square root of the previous value to the temporary variable.

Update the previous value with the square root.

Return the previous value.

Define the “main()” method,

Create array object for “SqrootProgression”.

Print the value returned from the method “firstValue()”.

Print the value returned from the method “nextValue()”.

Answer 8

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Answer 9

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Answer 10

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Answer 11

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