Chapter 20, Problem 1IR

To determine

The type of conic section of the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ .

Answer to Problem 1IR

The type of conic section of the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ is a circle.

Explanation of Solution

Given information:

The provided equation is ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ .

Consider the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ .

Use online graphing calculator to graph the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ ,

 

It can be observed from the above graph that the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ represents a circle with center $\left(7,2\right)$ .

Therefore, the type of conic section of the equation ${\left(x-7\right)}^2+{\left(y-2\right)}^2=4$ is a circle.