Chemistry (7th Edition)
Chemistry (7th Edition)
7th Edition
ISBN: 9780321943170
Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson
Publisher: PEARSON
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Chapter 20, Problem 20.1P
Interpretation Introduction

To determine:

The electron configuration of Co2+.

Concept introduction:

  • Electronic configuration of an atom shows how electrons are placed in the orbitals in order of increasing energy.
  • The filling of the sublevels progresses in order up to Period 4. However, in the sublevel blocks in Period 4 the 4s sublevel fills before the 3dsublevel.This occurs because the electrons in the 4ssublevel have slightly lower energy than the electrons in the 3d sublevel. This series of 10 elements is called the first transition series (3d).
  • 3d elements show large variation in their oxidation states.

Expert Solution
Check Mark

Answer to Problem 20.1P

Solution:Co2+

: 1s22s22p63s23p63d7

Explanation of Solution

Atomic number of cobalt is 27. Thus, it has 27 electrons in its elemental state.

The arrangement of atomic orbitals in increasing order of their energies is as follows:

1s2s2p3s3p4s3d

The maximum occupancy of electrons for s,p,anddorbitals is 2, 6, and 10 respectively.

Thus, electronic configuration will be:

1s22s22p63s23p64s23d7

Co2+has 2 electrons less than that in its elemental state, thus it has 25 electrons.

Now, electrons are first removed from 4s2orbitals.

Thus, the electronic configuration of Co2+will be:

1s22s22p63s23p63d7

(c)

Interpretation Introduction

To determine:

The electron configuration of metal in MnO2.

Concept introduction:

  • Electronic configuration of an atom shows how electrons are placed in the orbitals in order of increasing energy.
  • The filling of the sublevels progresses in order up to Period 4. However, in the sublevel blocks in Period 4 the 4s sublevel fills before the 3dsublevel.This occurs because the electrons in the 4ssublevel have slightly lower energy than the electrons in the 3d sublevel. This series of 10 elements is called the first transition series (3d).
  • 3d elements show large variation in their oxidation states.

Expert Solution
Check Mark

Answer to Problem 20.1P

Solution:MnO2

: 1s22s22p63s23p63d3

Explanation of Solution

Atomic number of manganese is 25. Thus, it has 25 electrons in its elemental state. The arrangement of atomic orbitals in increasing order of their energies is as follows:

1s2s2p3s3p4s3d

The electronic configuration will be:

1s22s22p63s23p64s23d5

Oxygen has an oxidation state of -2, thus in MnO2, 2 oxygen atoms have -4 charge on them. Since molecule is neutral, Mnmust have an atomic charge of +4. Thus, it has 4 electrons less than that in its elemental state, thus it has 21 electrons. The electrons are first removed from 4s orbital as follows:

1s22s22p63s23p63d3

(d)

Interpretation Introduction

To determine:

The electron configuration of metal in CuCl42.

Concept introduction:

  • Electronic configuration of an atom shows how electrons are placed in the orbitals in order of increasing energy.
  • The filling of the sublevels progresses in order up to Period 4. However, in the sublevel blocks in Period 4 the 4s sublevel fills before the 3dsublevel.This occurs because the electrons in the 4ssublevel have slightly lower energy than the electrons in the 3d sublevel. This series of 10 elements is called the first transition series (3d).
  • 3d elements show large variation in their oxidation states.

Expert Solution
Check Mark

Answer to Problem 20.1P

Solution:CuCl42: 1s22s22p63s23p63d9

Explanation of Solution

Atomic number of copper is 29. Thus, it has 29 electrons in its elemental state. The arrangement of atomic orbitals in increasing order of their energies is as follows:

1s2s2p3s3p4s3d

The maximum occupancy of electrons for s,p,anddorbitals is 2, 6, and 10 respectively.

Thus, the electronic configuration will be:

1s22s22p63s23p64s13d10

This is because half filled, and full filled orbitals are more stable.

Chlorine has an oxidation state of -1, thus in CuCl42, 4 chlorine atoms have -4 charge on them. Since molecule has a charge of -2, Cumust have an atomic charge of (4(2))=+2. Thus, it has 2 electrons less than that in its elemental state, thus it has 27 electrons.

Now filling up 27 electrons of Cu2+

to get its electronic configuration:

1s22s22p63s23p63d9

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Chapter 20 Solutions

Chemistry (7th Edition)

Ch. 20 - Prob. 20.11PCh. 20 - Prob. 20.12ACh. 20 - Prob. 20.13PCh. 20 - Prob. 20.14ACh. 20 - Prob. 20.15PCh. 20 - Prob. 20.16ACh. 20 - Prob. 20.17PCh. 20 - Prob. 20.18ACh. 20 - Prob. 20.19PCh. 20 - Prob. 20.20PCh. 20 - Prob. 20.21ACh. 20 - Prob. 20.22PCh. 20 - Prob. 20.23ACh. 20 - Prob. 20.24PCh. 20 - Prob. 20.25ACh. 20 - Prob. 20.26PCh. 20 - Prob. 20.27PCh. 20 - Prob. 20.28PCh. 20 - Prob. 20.29PCh. 20 - Prob. 20.30CPCh. 20 - Prob. 20.31CPCh. 20 - Prob. 20.32CPCh. 20 - Prob. 20.33CPCh. 20 - Prob. 20.34CPCh. 20 - Prob. 20.35CPCh. 20 - Prob. 20.36CPCh. 20 - Prob. 20.37CPCh. 20 - Prob. 20.38CPCh. 20 - Prob. 20.39CPCh. 20 - Prob. 20.40SPCh. 20 - Prob. 20.41SPCh. 20 - Prob. 20.42SPCh. 20 - Prob. 20.43SPCh. 20 - Titanium, used to make jet aircraft engines, is...Ch. 20 - Prob. 20.45SPCh. 20 - Prob. 20.46SPCh. 20 - Prob. 20.47SPCh. 20 - Prob. 20.48SPCh. 20 - Prob. 20.49SPCh. 20 - Prob. 20.50SPCh. 20 - Prob. 20.51SPCh. 20 - Prob. 20.52SPCh. 20 - Prob. 20.53SPCh. 20 - Prob. 20.54SPCh. 20 - Prob. 20.55SPCh. 20 - Prob. 20.56SPCh. 20 - Prob. 20.57SPCh. 20 - Prob. 20.58SPCh. 20 - Prob. 20.59SPCh. 20 - Prob. 20.60SPCh. 20 - Prob. 20.61SPCh. 20 - Prob. 20.62SPCh. 20 - Prob. 20.63SPCh. 20 - Prob. 20.64SPCh. 20 - Prob. 20.65SPCh. 20 - Prob. 20.66SPCh. 20 - Prob. 20.67SPCh. 20 - Prob. 20.68SPCh. 20 - Prob. 20.69SPCh. 20 - Prob. 20.70SPCh. 20 - Prob. 20.71SPCh. 20 - Prob. 20.72SPCh. 20 - Prob. 20.73SPCh. 20 - Prob. 20.74SPCh. 20 - Prob. 20.75SPCh. 20 - Prob. 20.76SPCh. 20 - Prob. 20.77SPCh. 20 - Prob. 20.78SPCh. 20 - Prob. 20.79SPCh. 20 - Prob. 20.80SPCh. 20 - Prob. 20.81SPCh. 20 - Prob. 20.82SPCh. 20 - Prob. 20.83SPCh. 20 - Prob. 20.84SPCh. 20 - Prob. 20.85SPCh. 20 - Prob. 20.86SPCh. 20 - Prob. 20.87SPCh. 20 - Prob. 20.88SPCh. 20 - Prob. 20.89SPCh. 20 - Prob. 20.90SPCh. 20 - Prob. 20.91SPCh. 20 - Prob. 20.92SPCh. 20 - Prob. 20.93SPCh. 20 - Prob. 20.94SPCh. 20 - Prob. 20.95SPCh. 20 - Prob. 20.96SPCh. 20 - Prob. 20.97SPCh. 20 - Prob. 20.98SPCh. 20 - Prob. 20.99SPCh. 20 - Prob. 20.100SPCh. 20 - Prob. 20.101SPCh. 20 - Prob. 20.102SPCh. 20 - Prob. 20.103SPCh. 20 - Prob. 20.104SPCh. 20 - Prob. 20.105SPCh. 20 - Prob. 20.106SPCh. 20 - Prob. 20.107SPCh. 20 - Prob. 20.108SPCh. 20 - Prob. 20.109SPCh. 20 - Prob. 20.110SPCh. 20 - Prob. 20.111SPCh. 20 - Prob. 20.112SPCh. 20 - Prob. 20.113SPCh. 20 - Prob. 20.114SPCh. 20 - Prob. 20.115SPCh. 20 - Prob. 20.116SPCh. 20 - Prob. 20.117SPCh. 20 - Prob. 20.118SPCh. 20 - Prob. 20.119SPCh. 20 - Prob. 20.120SPCh. 20 - Prob. 20.121SPCh. 20 - Prob. 20.122SPCh. 20 - Prob. 20.123SPCh. 20 - Prob. 20.124CPCh. 20 - Prob. 20.125CPCh. 20 - Prob. 20.126CPCh. 20 - Prob. 20.127CPCh. 20 - Prob. 20.128CPCh. 20 - Prob. 20.129CPCh. 20 - Prob. 20.130CPCh. 20 - Prob. 20.131CPCh. 20 - Prob. 20.132CPCh. 20 - Prob. 20.133CPCh. 20 - Prob. 20.134CPCh. 20 - Prob. 20.135CPCh. 20 - Prob. 20.136CPCh. 20 - Prob. 20.137CPCh. 20 - Prob. 20.138CPCh. 20 - Prob. 20.139CPCh. 20 - Prob. 20.140CPCh. 20 - Prob. 20.141CPCh. 20 - Prob. 20.142CPCh. 20 - Prob. 20.143CPCh. 20 - Prob. 20.144CPCh. 20 - Prob. 20.145CPCh. 20 - Prob. 20.146CPCh. 20 - Prob. 20.147CPCh. 20 - Prob. 20.148CPCh. 20 - Prob. 20.149MPCh. 20 - Prob. 20.150MPCh. 20 - Prob. 20.151MPCh. 20 - Prob. 20.152MPCh. 20 - Prob. 20.153MPCh. 20 - Prob. 20.154MPCh. 20 - Prob. 20.155MPCh. 20 - Prob. 20.156MPCh. 20 - Prob. 20.157MP
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