Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Chapter 20, Problem 36A
To determine

Value of each charges.

Expert Solution & Answer
Check Mark

Answer to Problem 36A

  q1=q2=3.2×1019C

Explanation of Solution

Given:

Two identical charges with repulsive force F=6.4×109N

Distance between the charges, d=3.8×1010m

Formula Used:

From Coulomb’s law,

  F=Kq1q2d2

Where,

  F is electrostatic force

  K is coulomb’s constant

  q1 and q2 are charges and

  d is distance between the charges.

Calculation:

As, K=9×109N.m2/C2

On putting the values,

  6.4×109=9×109×(q1)×(q2)(3.8×1010)2

As both charges are identical,

So, let q1=q2=q

Therefore,

  6.4×109=9×109×(q)×(q)(3.8×1010)2q2=(6.4×109)(3.8×1010)29×109q=(6.4×109)(3.8×1010)29×109=3.2×1019C

Conclusion:

Therefore, the charges are q1=q2=3.2×1019C .

Chapter 20 Solutions

Glencoe Physics: Principles and Problems, Student Edition

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