Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 20, Problem 38P
To determine
To Show:The cost of air conditioning isproportional to
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A typical electric refrigerator has a power ratingof 400 W, which is the rate (in J/s) at whichelectrical energy is supplied to do the work neededto remove heat from the refrigerator. If therefrigerator releases heat to the room at a rate of900 W, at what rate (in watts) does it remove heatfrom the inside of the refrigerator?
A 50-m-long section of a steam pipe whose outer diameteris 10 cm passes through an open space at 15°C. The averagetemperature of the outer surface of the pipe is measured to be150°C. If the combined heat transfer coefficient on the outer surfaceof the pipe is 20 W/m2·K, determine (a) the rate of heat lossfrom the steam pipe; (b) the annual cost of this energy lost if steamis generated in a natural gas furnace that has an efficiency of 75percent and the price of natural gas is $0.52/therm (1 therm =105,500 kJ); and (c) the thickness of fiberglass insulation(k = 0.035 W/m·K) needed in order to save 90 percent of the heatlost. Assume the pipe temperature to remain constant at 150°C.
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Chapter 20 Solutions
Physics for Scientists and Engineers
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- Check your Understanding Show that QhQh=QcQc for the hypothetical engine of Figure 4.10 The second property to be demonstrated is that all reversible engines operating between the same two reservoirs have the same efficiency. To this, stat with the two engines D and E of Figure 4.10 (a), which are operating between two common heat reservoirs at temperatures Th and Tc . First, assume that D is a reversible engine and that E is a hypothetical irreversible engine that has a higher efficiency than D. If both engines perform the same amount of work W per cycle, it follows from Equation 4.2 that QhQh . It then follows from the first law that QcQc . Figure 4.10 (a) Two uncoupled engines D and E working between the same reservoirs. (b) The engines, With D working reverse. Suppose the cycle of D is so that it operates as a refrigerator, and the two engines are coupled such that the work output of E is used to drive D, as shown in Figure 4.10(b). Since QhQh and QcQc , the net result of each cycle is equivalent to a spontaneous transfer of heat from the cold reservoir to the hot reservoir, a process second law does not allow. The original assumption must therefore be wrong, and it is impossible to construct an irreversible engine such that E is more efficient than the reversible engine D. Now it is quite easy to demonstrate that the efficiencies of all reversible engines operating between the same reservoirs are equal. Suppose that D and E are reversible engines. If they are as shown in Figure 4.10(b), the efficiency of E cannot be greater than the efficiency of D, or second law would violated. If both engines are then reversed, the same reasoning implies that the efficiency of D cannot be greater than the efficiency of E. Combining these results leads to the conclusion that all reversible engines working between same two reservoirs have the same efficiency.arrow_forwardThe energy output of a heat pump is greater than the energy used to operate the pump. Why doesn't this statement violate the first law of thermodynamics?arrow_forwardIn a quasi-static isobaric expansion, 500 J of work are done by the gas. The gas pressure is 0.80 atm and it was originally at 20.0 L. If the internal energy of the gas increased by 80 J in the expansion, how much heat does the gas absorb?arrow_forward
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