Chapter 20, Problem 50IL

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The mineral claudetite contains the element arsenic in the form of arsenic(III) oxide, As2O3. The As2O3 in a 0.562-g sample of the impure mineral was converted first to H3AsO3 and then titrated with a 0.0480 M solution of I3−, which reacts with H3AsO3 according to the following balanced net ionic equationH3AsO3(aq) + 3 H2O(ℓ) + I3−(aq) → H3AsO4(aq) + 2 H3O+(aq) + 3 I−(aq)If the titration required 45.7 mL of the I3− solution, what is the percentage of As2O3 in the mineral sample?

Interpretation Introduction

Interpretation: The percentage of As2O3 in the mineral sample should be determined.

Concept introduction:

Concentration of a solution can be expressed in molarity.

Molarity=NumberofmolesVolumeofsolutioninlitres

Numberofmoles=massmolarmass

Explanation

Given:

H3AsO3â€‰â€‰â€‰+â€‰â€‰3â€‰H2Oâ€‰â€‰+â€‰I3-â€‰â€‰â€‰â†’â€‰â€‰H3AsO4â€‰â€‰+â€‰2â€‰H3O+â€‰â€‰+â€‰â€‰3â€‰I-â€‰

Massâ€‰ofâ€‰sampleâ€‰â€‰=â€‰0.562â€‰g

Given that 0.0480â€‰Mâ€‰I3- reacts with H3AsO3â€‰

From the equation it is clear that one mole of H3AsO3â€‰ reacts with one mole of I3- to give the product.

Molarityâ€‰â€‰=â€‰Numberâ€‰ofâ€‰molesVolumeâ€‰ofâ€‰solutionâ€‰inâ€‰litres

Numberâ€‰ofâ€‰molesâ€‰â€‰â€‰â€‰=â€‰â€‰Molarityâ€‰â€‰Ã—â€‰Volumeâ€‰ofâ€‰solutionâ€‰inâ€‰litresâ€‰

Numberâ€‰ofâ€‰molesâ€‰ofâ€‰I3-â€‰â€‰â€‰=â€‰â€‰Molarityâ€‰â€‰Ã—â€‰Volumeâ€‰ofâ€‰solutionâ€‰inâ€‰litresâ€‰â€‰=â€‰0

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