Explanation Given information: The density of liquid is 900 kg / m 3 , the volumetric flow rate of calorimeter is 2.00 L / min , temperature difference established between the input and output points is 3.50 °C , energy is supplied at the rate of 200 W . The expression for the calculation of mass flow rate of liquid is given as, m ˙ = ρ × v ˙ v ˙ is the volumetric flow rate. m ˙ is the mass flow rate. ρ is the density of liquid. Substitute 900 kg / m 3 for ρ and 2.00 L / min for v ˙ in the above equation. m ˙ = 900 kg / m 3 × 2.00 L / min = 900 kg / m 3 × 2.00 × 1 L 1 min × 0.001 m 3 1 L × 1 min 60 sec = 0

Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)

9th Edition

ISBN: 9781305266292

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 20, Problem 63AP

To determine

The specific heat of the liquid.

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Chapter 20, Problem 62AP

Chapter 20, Problem 64AP

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Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)

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