Chemistry (Looseleaf) - With Student Solutions Manual
3rd Edition
ISBN: 9780077822828
Author: Burdge
Publisher: MCG
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Chapter 20.2, Problem 1PPC
Practice Problem CONCEPTUALIZE
Which of the following graphs best represents the relationship between energy released
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BRINE SOLUTION PROBLEM:
Carbon-14 is a radioactive isotope of carbon that has a half-life of 5600 years. It is used extensively in dating organic material that is tens of thousands of years old. What fraction of the original amount of Carbon-14 in a sample would be present after 10,000 years?
Radioactive radon-222, found in many homes, is a potential health hazard.
The half-life of radon-222 is 3.82 days. If you begin with 75.5 milligrams of radon-222, how many milligrams will you have left after 11.5 days have passed?
__________-mg
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A cup of hot coffee initially at 100°C cools to 90°C after 15 minutes in a room at TS = 65°C.
T = (T0 – TS) e–kt + TS
What is the value of the decay constant k?
Question 8 options:
1.56 min–1
0.0224 min–1
0.381 min–1
What is the coffee temperature after 60 minutes?
Question 9 options:
74.1°C
81.0°C
77.3°C
How much time is required for the coffee to cool to 80°C?
Question 10 options:
42.8 minutes
37.8 minutes
32.3 minutes
Chapter 20 Solutions
Chemistry (Looseleaf) - With Student Solutions Manual
Ch. 20.1 - Practice Problem ATTEMPT
Identify X in each of...Ch. 20.1 - Prob. 1PPBCh. 20.1 - Practice Problem CONCEPTUALIZE
For each process,...Ch. 20.1 - Prob. 1CPCh. 20.1 - Prob. 2CPCh. 20.2 - Prob. 1PPACh. 20.2 - Prob. 1PPBCh. 20.2 - Practice Problem CONCEPTUALIZE Which of the...Ch. 20.2 - Prob. 1CPCh. 20.2 - Prob. 2CP
Ch. 20.2 - Prob. 3CPCh. 20.2 - Prob. 4CPCh. 20.3 - Prob. 1PPACh. 20.3 - Prob. 1PPBCh. 20.3 - Practice Problem CONCEPTUALIZE
The Think About It...Ch. 20.3 - Prob. 1CPCh. 20.3 - Prob. 2CPCh. 20.3 - Prob. 3CPCh. 20.4 - Practice Problem ATTEMPT Determine the age of a...Ch. 20.4 - Practice Problem BUILD How much 206 Pb will be in...Ch. 20.4 - Prob. 1PPCCh. 20.4 - Prob. 1CPCh. 20.4 - Prob. 2CPCh. 20.5 - Prob. 1PPACh. 20.5 - Prob. 1PPBCh. 20.5 - Practice Problem CONCEPTUALIZE
One of the major...Ch. 20 - Prob. 1QPCh. 20 - Prob. 2QPCh. 20 - Prob. 3QPCh. 20 - Prob. 4QPCh. 20 - Prob. 5QPCh. 20 - Prob. 6QPCh. 20 - Prob. 7QPCh. 20 - Prob. 8QPCh. 20 - 20.9 why is it impossible for the isotope to...Ch. 20 - Prob. 10QPCh. 20 - Prob. 11QPCh. 20 - Prob. 12QPCh. 20 - Prob. 13QPCh. 20 - For each pair of isotopes listed, predict which...Ch. 20 - Prob. 15QPCh. 20 - Prob. 16QPCh. 20 - Prob. 17QPCh. 20 - Prob. 18QPCh. 20 - Prob. 19QPCh. 20 - Prob. 20QPCh. 20 - Prob. 21QPCh. 20 - Prob. 22QPCh. 20 - Prob. 23QPCh. 20 - Prob. 24QPCh. 20 - Prob. 25QPCh. 20 - Prob. 26QPCh. 20 - Prob. 27QPCh. 20 - Prob. 28QPCh. 20 - Prob. 29QPCh. 20 - Prob. 30QPCh. 20 - Prob. 31QPCh. 20 - Prob. 32QPCh. 20 - Prob. 33QPCh. 20 - Prob. 34QPCh. 20 - Prob. 35QPCh. 20 - Prob. 36QPCh. 20 - Prob. 37QPCh. 20 - Prob. 38QPCh. 20 - Prob. 39QPCh. 20 - Prob. 40QPCh. 20 - Prob. 41QPCh. 20 - Prob. 42QPCh. 20 - Prob. 43QPCh. 20 - Prob. 44QPCh. 20 - Prob. 45QPCh. 20 - Prob. 46QPCh. 20 - Prob. 47QPCh. 20 - Prob. 48QPCh. 20 - Prob. 49QPCh. 20 - Prob. 50QPCh. 20 - Prob. 51QPCh. 20 - Prob. 52QPCh. 20 - Prob. 53QPCh. 20 - Prob. 54QPCh. 20 - Prob. 55QPCh. 20 - Prob. 56QPCh. 20 - Prob. 57QPCh. 20 - Prob. 58QPCh. 20 - Prob. 59QPCh. 20 - Prob. 60QPCh. 20 - Prob. 61QPCh. 20 - Prob. 62APCh. 20 - Prob. 63APCh. 20 - Prob. 64APCh. 20 - Prob. 65APCh. 20 - Prob. 66APCh. 20 - Prob. 67APCh. 20 - Prob. 68APCh. 20 - Prob. 69APCh. 20 - Prob. 70APCh. 20 - Prob. 71APCh. 20 - Prob. 72APCh. 20 - Prob. 73APCh. 20 - Prob. 74APCh. 20 - Prob. 75APCh. 20 - Prob. 76APCh. 20 - Prob. 77APCh. 20 - Prob. 78APCh. 20 - Prob. 79APCh. 20 - Prob. 80APCh. 20 - Prob. 81APCh. 20 - Prob. 82APCh. 20 - Prob. 83APCh. 20 - Prob. 84APCh. 20 - Prob. 85APCh. 20 - Prob. 86APCh. 20 - Prob. 87APCh. 20 - Prob. 88APCh. 20 - Prob. 89APCh. 20 - Prob. 90APCh. 20 - Prob. 91APCh. 20 - Prob. 92APCh. 20 - Prob. 93APCh. 20 - Prob. 94APCh. 20 - Prob. 95APCh. 20 - Prob. 96APCh. 20 - Prob. 97APCh. 20 - Prob. 98APCh. 20 - Prob. 99APCh. 20 - Prob. 100APCh. 20 - Prob. 101APCh. 20 - Prob. 102APCh. 20 - Prob. 103APCh. 20 - Prob. 1SEPPCh. 20 - Prob. 2SEPPCh. 20 - Prob. 3SEPPCh. 20 - Prob. 4SEPP
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- Problem 9-2 Thorium-223 is an alpha emitter. Write an equation for this nuclear reaction and identify the product formed.arrow_forwardProblem 9-6 A radioactive isotope in a 9.0-mL vial has an intensity of 300. mCi. A patient is required to take 50. mCi intravenously. How much liquid should be used for the injection?arrow_forwardco-60 is used for radiation therapy as implants and as external source of radiation exposure. The half life of Co-60 is 5,272 years. how much of a 2.000 mg sample will remain after 21,088 years? Please show work.arrow_forward
- Problem 9-1 Iodine-139 is a beta emitter. Write an equation for this nuclear reaction and identify the product formed.arrow_forwardBRINE SOLUTION PROBLEM: In 1986 the Chernobyl nuclear power plant exploded, and scattered radioactive material over Europe. Of particular note were the two radioactive elements iodine-131 whose half-life is 8 days and cesium-137 whose half-life is 30 years. Predict how much of this material would remain over time. Express your final answer as a function of t.arrow_forwardWhich of the following transformations is (are) fusion: helium to carbon, carbon to iron, uranium to lead, boron to carbon, oxygen to neon? (Select all that apply. See Appendix K for a list of the elements.) helium to carbon carbon to iron uranium to lead boron to carbon oxygen to neonarrow_forward
- How did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs 0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours _________ ng sodium -24 remain check_circle Expert Answer thumb_up thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.arrow_forwardIf pure polonium-210 (k = 5.02 x 10-3 day-1) were used in a crime, based on radioactive disintegration alone, how long would it take for 30% the original isotope to disappear?Exact answerarrow_forwardPlutonium-239 is a radioactive waste from nuclear reactors and has a half-life of 25,000 years. How many years must a 100g sample of Pu-239 be stored until only 0.049g of the Pu-239 remains? a. 2.5 x 104 years b. 1.9 x 105 years c. 2.8 x 105 years d. 5.6 x 106 years e. no correct response is givenarrow_forward
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