Chemistry
Chemistry
4th Edition
ISBN: 9780078021527
Author: Julia Burdge
Publisher: McGraw-Hill Education
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Chapter 20.4, Problem 1PPC
Interpretation Introduction

Interpretation:

The diagram that represents the sample of X after 105 days is to be determined.

Concept introduction:

Half-life of a reaction is defined as the time in which the reactant concentration becomes half. In other words, it is the time required for 50% completion of the reaction.

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BRINE SOLUTION PROBLEM: Carbon-14 is a radioactive isotope of carbon that has a half-life of 5600 years. It is used extensively in dating organic material that is tens of thousands of years old. What fraction of the original amount of Carbon-14 in a sample would be present after 10,000 years?
Phosphorus-32 is used in biochemical studies to follow the pathway taken by metabolites. Its half-life is 14.3 days. A vial containing 10 microgram of P-32 is accidentally spilled into a sink.  Use the GRS (Given-Required-Solution) format of problem solving. a. How long will it take P-32 in the drain to exhibit 68% of its original activity?b. How many atoms of P-32 remain in the sink after 755 days?
How did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs   0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours    _________ ng sodium -24 remain  check_circle Expert Answer thumb_up   thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.

Chapter 20 Solutions

Chemistry

Ch. 20.2 - Prob. 3CPCh. 20.2 - Prob. 4CPCh. 20.3 - Prob. 1PPACh. 20.3 - Prob. 1PPBCh. 20.3 - Practice Problem CONCEPTUALIZE The Think About It...Ch. 20.3 - Prob. 1CPCh. 20.3 - Prob. 2CPCh. 20.3 - Prob. 3CPCh. 20.4 - Practice Problem ATTEMPT Determine the age of a...Ch. 20.4 - Practice Problem BUILD How much 206 Pb will be in...Ch. 20.4 - Prob. 1PPCCh. 20.4 - Prob. 1CPCh. 20.4 - Prob. 2CPCh. 20.5 - Prob. 1PPACh. 20.5 - Prob. 1PPBCh. 20.5 - Practice Problem CONCEPTUALIZE One of the major...Ch. 20 - Prob. 1QPCh. 20 - Prob. 2QPCh. 20 - Prob. 3QPCh. 20 - Prob. 4QPCh. 20 - Prob. 5QPCh. 20 - Prob. 6QPCh. 20 - Prob. 7QPCh. 20 - Prob. 8QPCh. 20 - 20.9 why is it impossible for the isotope to...Ch. 20 - Prob. 10QPCh. 20 - Prob. 11QPCh. 20 - Prob. 12QPCh. 20 - Prob. 13QPCh. 20 - For each pair of isotopes listed, predict which...Ch. 20 - Prob. 15QPCh. 20 - Prob. 16QPCh. 20 - Prob. 17QPCh. 20 - Prob. 18QPCh. 20 - Prob. 19QPCh. 20 - Prob. 20QPCh. 20 - Prob. 21QPCh. 20 - Prob. 22QPCh. 20 - Prob. 23QPCh. 20 - Prob. 24QPCh. 20 - Prob. 25QPCh. 20 - Prob. 26QPCh. 20 - Prob. 27QPCh. 20 - Prob. 28QPCh. 20 - Prob. 29QPCh. 20 - Prob. 30QPCh. 20 - Prob. 31QPCh. 20 - Prob. 32QPCh. 20 - Prob. 33QPCh. 20 - Prob. 34QPCh. 20 - Prob. 35QPCh. 20 - Prob. 36QPCh. 20 - Prob. 37QPCh. 20 - Prob. 38QPCh. 20 - Prob. 39QPCh. 20 - Prob. 40QPCh. 20 - Prob. 41QPCh. 20 - Prob. 42QPCh. 20 - Prob. 43QPCh. 20 - Prob. 44QPCh. 20 - Prob. 45QPCh. 20 - Prob. 46QPCh. 20 - Prob. 47QPCh. 20 - Prob. 48QPCh. 20 - Prob. 49QPCh. 20 - Prob. 50QPCh. 20 - Prob. 51QPCh. 20 - Prob. 52QPCh. 20 - Prob. 53QPCh. 20 - Prob. 54QPCh. 20 - Prob. 55QPCh. 20 - Prob. 56QPCh. 20 - Prob. 57QPCh. 20 - Prob. 58QPCh. 20 - Prob. 59QPCh. 20 - Prob. 60QPCh. 20 - Prob. 61QPCh. 20 - Prob. 62APCh. 20 - Prob. 63APCh. 20 - Prob. 64APCh. 20 - Prob. 65APCh. 20 - Prob. 66APCh. 20 - Prob. 67APCh. 20 - Prob. 68APCh. 20 - Prob. 69APCh. 20 - Prob. 70APCh. 20 - Prob. 71APCh. 20 - Prob. 72APCh. 20 - Prob. 73APCh. 20 - Prob. 74APCh. 20 - Prob. 75APCh. 20 - Prob. 76APCh. 20 - Prob. 77APCh. 20 - Prob. 78APCh. 20 - Prob. 79APCh. 20 - Prob. 80APCh. 20 - Prob. 81APCh. 20 - Prob. 82APCh. 20 - Prob. 83APCh. 20 - Prob. 84APCh. 20 - Prob. 85APCh. 20 - Prob. 86APCh. 20 - Prob. 87APCh. 20 - Prob. 88APCh. 20 - Prob. 89APCh. 20 - Prob. 90APCh. 20 - Prob. 91APCh. 20 - Prob. 92APCh. 20 - Prob. 93APCh. 20 - Prob. 94APCh. 20 - Prob. 95APCh. 20 - Prob. 96APCh. 20 - Prob. 97APCh. 20 - Prob. 98APCh. 20 - Prob. 99APCh. 20 - Prob. 100APCh. 20 - Prob. 101APCh. 20 - Prob. 102APCh. 20 - Prob. 103APCh. 20 - Prob. 1SEPPCh. 20 - Prob. 2SEPPCh. 20 - Prob. 3SEPPCh. 20 - Prob. 4SEPP
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