CHEM: STRUC & PROP (LL) VOL 2 >C PKG<
2nd Edition
ISBN: 9780137390922
Author: Tro
Publisher: PEARSON C
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Chapter 21, Problem 107E
Interpretation Introduction
To determine:
The monochlorination product ratio and reactivity ratio of given propane.
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Consider the following changes:a.N2 (g) → N2 (l)b.CO (g) + H2O (g) → H2 (g) + CO2 (g)c.Ca3P2 (s) + 6H2O (l) → 3Ca(OH)2 (s) + 2PH3 (g)d.2CH3OH (l) + 3O2 (g) → 2CO2 (g) + 4H2O (l)e. I2 (s) → I2 (g)At constant temperature and pressure, in which of these changes is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done?
D21 1120 Ch-13 Homework - General Chemistry II
W 1120 Ch-12 Homewart
Write a balanced chemical equation for each reaction. (Include states-of-matter under the given conditions in your answer.)
(a) combustion of acetylene (ethyne, C₂H₂(g)) to form carbon dioxide gas and water vapor
The reactants are acetylene and oxygen (because this is a combustion reaction) and the products are carbon dioxide gas and water. The
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(b) synthesis of NO(g) from N₂O(g) and NO₂(g)
The reactants are N₂O and NO2, and the product is NO. The balanced chemical equation is the following.
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(c) reaction of solid carbon graphite with water vapor to produce carbon monoxide gas and hydrogen gas
The reactants are C and H₂O, and the products are CO and H₂. The balanced chemical equation is the following.
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Choose the reaction that represents the combustion of C6H1202.
C6H12O2(1) + 8 O2(g) →6 CO2(g) + 6 H₂O(g)
O Mg(s) + C6H1202(1)→ MgC6H₁202(aq)
6 C(s) + 6 H₂(g) + O2(g) → C6H12O2(1)
C6H12O2(1)→6 C(s) + 6 H₂(g) + O2(g)
None of these represent the combustion of C6H12O2.
Chapter 21 Solutions
CHEM: STRUC & PROP (LL) VOL 2 >C PKG<
Ch. 21 - Prob. 1ECh. 21 - Prob. 2ECh. 21 - Prob. 3ECh. 21 - Prob. 4ECh. 21 - Prob. 5ECh. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - What are the main classifications of hydrocarbons?...Ch. 21 - Prob. 9ECh. 21 - What are structural isomers? How do the properties...
Ch. 21 - Prob. 11ECh. 21 - Define each term related to optical isomerism:...Ch. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Explain geometric isomerism in alkenes. How do the...Ch. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Prob. 25ECh. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Name each alkane.Ch. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Draw a structure for each alkane. a....Ch. 21 - Prob. 45ECh. 21 - Complete and balance each hydrocarbon combustion...Ch. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Prob. 50ECh. 21 - Name each alkene.Ch. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Name each alkyne.Ch. 21 - Draw the correct structure for each compound. a....Ch. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - Prob. 76ECh. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80ECh. 21 - Prob. 81ECh. 21 - Prob. 82ECh. 21 - Prob. 83ECh. 21 - Prob. 84ECh. 21 - Prob. 85ECh. 21 - Prob. 86ECh. 21 - Prob. 87ECh. 21 - Prob. 88ECh. 21 - Identify each organic compound as an alkane,...Ch. 21 - Identify each organic compound as an alkane,...Ch. 21 - Prob. 91ECh. 21 - Prob. 92ECh. 21 - Prob. 93ECh. 21 - Determine whether each pair of structures are...Ch. 21 - Prob. 95ECh. 21 - Prob. 96ECh. 21 - Classify each organic reaction as combustion,...Ch. 21 - Prob. 98ECh. 21 - Prob. 99ECh. 21 - Prob. 100ECh. 21 - Prob. 101ECh. 21 - Prob. 102ECh. 21 - Prob. 103ECh. 21 - Prob. 104ECh. 21 - Prob. 105ECh. 21 - Prob. 106ECh. 21 - Prob. 107ECh. 21 - Prob. 108ECh. 21 - Prob. 109ECh. 21 - Prob. 110ECh. 21 - Prob. 111ECh. 21 - Prob. 112ECh. 21 - Prob. 113ECh. 21 - Prob. 114ECh. 21 - Draw the structure and name a compound with the...Ch. 21 - Prob. 116ECh. 21 - Prob. 117ECh. 21 - Prob. 118ECh. 21 - Prob. 119ECh. 21 - Prob. 120ECh. 21 - Prob. 121ECh. 21 - Prob. 1SAQCh. 21 - Prob. 2SAQCh. 21 - Prob. 3SAQCh. 21 - Prob. 4SAQCh. 21 - Prob. 5SAQCh. 21 - Prob. 6SAQCh. 21 - Prob. 7SAQCh. 21 - Prob. 8SAQCh. 21 - Prob. 9SAQCh. 21 - Prob. 10SAQ
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- Consider the following changes: a. N2(g) →N2(l) b. CO (g) + H2O(g) →H2(g)+CO2(g) c. Ca3P2(s)+6H2O(l) → 3Ca(OH)2(s)+2PH3(g) d. 2CH3OH(l)+3O2(g) →2CO2(g)+4H2O(l) e. I2(s) →I2(g)At constant temperature and pressure, in which of these changes is workdone by the system on the surroundings? By the surroundings on the system? In which of them is no work done?arrow_forwardA Moving to the next question prevents changes to this answer. Question 2 Calculate AH for the formation of benzoic acid from its constituent elements 7C(s) + 3H2(g) + O₂(g) → C6H5COOH(s) Given: C6H5COOH(s) + 15/2 O2(g) → 7CO2(g) + 3H₂O(l) C(s) + O2(g) - CO₂(g) H2(g) + O2(g) → H₂O(l) Attach File Browse Local Files AH = -771.2 kcal AH-94.05 kcal AH = -68.32 kcal Moving to the next question prevents changes to this answer. (2) (3)arrow_forwardCH,(9) + 2 O,(g) AH = -809.0 kJ/mol rxn Co,(9) + 2 H,0(g) ΔΗ. = -81.3 kJ 'cond 2 H,0U) Given the energy diagram above, what is AH when two moles of methane are combusted? -401.15 kJ +1604.6 kJ -802.3 kJ +802.3 kJ +401.15 kJ O -1604.6 kJarrow_forward
- For the steam hydrocarbon reforming process, the equilibrium law expression is [CO₂(g)][H₂(g)]* [CH][H₂0² Kc The reaction described by this equilibrium is CH4 (a) + H₂O(g) = CO₂(g) + H₂(g) CH4 (q) + 2H₂O(g) = CO₂(g) + 4H₂(g) CO₂(g) + 4H₂(g) = CH₁ (a) +2H₂O(g) CO₂(g) + H₂ (a) CH4 (q) + H₂O(g)arrow_forwardCH2=CH2(g) + H2(g) CH3CH3 (g) is an example of . 5. This reaction: action. re- 6. It involves the addition of oxygen to a compound, which changes the functional group that is present is known as 7. An important biological molecule that has an amine functional group on one end of the mole- cule and a carboxylic acid functional group on the other end is known as reaction.arrow_forwardWrite a balanced chemical equation for the hypothetical reaction of liquid dichloromethane, CH2CI2, with solid NaAaBb3 to form solid CH2(AaBb3)2 and another product.arrow_forward
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- Based on the nature of reactants and products, determine which of the following potential energy diagrams corresponds to this chemical reaction: 2 NO(g) + O₂(g) → 2 NO₂(g) Ep 1 Reactants Products Ep T g Redan Producta I Rascania Productsarrow_forwardThe diagram below shows steps in the exothermic chemical reaction of bromomethane with hydroxide to form methanol and bromide ion. The black spheres are carbon atoms, the white spheres are hydrogen atoms, the red spheres are oxygen atoms, and the blue dots are bromine atoms. Write a balanced chemical equation to represent the reaction. Draw an energy diagram similar in style to the one in question #1 of the reaction in which you label the energies of each step in the reaction and the activation energy. Your diagram should include the reactants, activation energy, transition state, and products. Indicate if it is endothermic or exothermic. You may draw this on paper and attach an image file to your assignment. Using the figures in the diagram above, include these figures A, B and C on your energy diagram at the steps of the reaction in the correct order, label each molecule in the drawings. Describe what is happening in the reaction you just drew at each phase as time…arrow_forward2. Write the name(s) of the product(s) for the following reactions. If no reaction can occur, write "no reaction" and briefly explain why. *** The catalyst for the 4th reaction is H+ CH3 H₂SO4 180C OH OH CH, CCH, CH, CH3 [H] KMnO₂arrow_forward
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