Concept explainers
Interpretation: The ions of alanine that predominate in a solution of
Concept introduction: Alanine is defined as an amino acid which contains
To determine: The ions of alanine that predominate in a solution of
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EBK CHEMISTRY: AN ATOMS FIRST APPROACH
- A scientist is comparing two lakes. She finds that water samples from Lake X have a pH of 3.50 and water samples from Lake Y have a pH of 5.50. Therefore, it can be said that Lake X has a hydronium ion concentration that is times greater than Lake Y.arrow_forwardConsider the following data on some weak acids and weak bases: acid base K. Kb name formula name formula HCH,CO, 1.8 × 10¬ ethylamine C2H5NH2|6.4 × 10 acetic acid 8 3.0 x 10 4 hypochlorous acid HCIO methylamine CH3NH2 |4.4 × 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M NaCIО choose one 0.1 М КCН3СО2 choose one 0.1 M C2H5NH3CI choose one 0.1 М CH3NH3Br choose onearrow_forwardThe acid dissociation constant K of trimethylacetic acid (HC(CH³)₂CO₂) is 9.33 × 10¯6. a Calculate the pH of a 3.6M solution of trimethylacetic acid. Round your answer to 1 decimal place. pH = - 0 X Śarrow_forward
- Morphine is an effective pain killer but is also highly addictive. Calculate the pH of a 0.115 M solution of morphine if its pKb = 5.79.arrow_forwardConsider the following data on some weak acids and weak bases: acid base Ka name formula name formula hydrocyanic acid НCN - 10 4.9 x 10 methylamine CH3NH2 |4.4 × 10 hypochlorous acid HC1O 8. 3.0 × 10 ethylamine C2H,NH,|6.4 × 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M C2H5NH3CI choose one 0.1 M NaCN choose one 0.1 M NaCi choose one 0.1 М CН3NH3B choose onearrow_forwardConsider the following data on some weak acids and weak bases: acid base Ка K₂ name formula name formula 4 hypochlorous acid HCIO 3.0 × 10 ethylamine C₂H5NH₂ 6.4 × 107 acetic acid HCH3CO₂ 1.8 × 10 methylamine CH3NH₂ 4.4×10¯ " Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a 2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 M C₂H5NH3CI ✓ choose one 1 (lowest) 0.1 M CH3NH3Br 2 3 0.1 M KNO3 4 (highest) 0.1 M NACIO choose one ✓arrow_forward
- For H2CO3, Ka1 = 4.3 × 10–7, Ka2 = 4.7 × 10–11. What is the pH of a 0.36 M solution of carbonic acid?arrow_forwardpH = −log[H+] where [H+] is the hydrogen ion concentration, measured in moles per liter. Solutions with a pH-value of less than 7 are acidic; solutions with a pH-value of greater than 7 are basic; solutions with a pH-value of 7 (such as pure water) are neutral. Black coffee has a pH of 5 and pure water has a pH of 7. Compare the pH of each and determine how much more acidic black coffee is than pure water.arrow_forwardAscorbic acid, H2C6H6O2, is a diprotic acid. The values of Ka1 and Ka2 are 7.9 × 10–5 and 1.6 × 10–12, respectively. What is the pH of a 0.80 M solution of ascorbic acid? Provide your answer to two decimal places and without units. Avoid using scientific notation.arrow_forward
- Calculate the pH at 25°C of a 0.91 M solution of anilinium chloride (C6H5NH3Cl). Note that aniline (C6H5NH2) is a weak base with a pKb of 4.87.arrow_forwardConsider the following data on some weak acids and weak bases: acid base Ka name formula name formula HCH3CO2 1.8 × 10 C,H;NH, 4.3 × 10 5 10 acetic acid aniline hydrofluoric acid HF 6.8 x 10 ethylamine C2H;NH2| 6.4 x 10 Use this data to rank the following solutions in order of increasing pH. In other words, select a 'l' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. solution pH 0.1 М KF choose one 0.1 M C2H5NH3CI choose one 0.1 M NaCl choose one 0.1 M NaCH3CO2 choose onearrow_forwardA 20 ml solution of 0.1 M glycine hydrochloride has been prepared. How many moles of the weak acid and conjugate base forms of glycine are present after the addition of 620 µl of 1.0 M NaOH? What is the pH of the resulting solution?arrow_forward
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