Chapter 21, Problem 21.90P

Interpretation Introduction

Interpretation:

The $\text{pH}$ of the solution that results from the addition of $\text{25mL of 0}{\text{.200 M KOH}}_{\left(\text{aq}\right)}$ to $\text{50mL of 0}{\text{.150M HNO}}_{\text{2}\left(\text{aq}\right)}$ has to be calculated.

Concept Introduction:

In the quantitative analysis the unknown concentration can be calculated using volumetric principle

  $\begin{array}{l}{\text{M}}_{\text{1}}{\text{V}}_{\text{1}}{\text{=M}}_{\text{2}}{\text{V}}_{\text{2}}\\ \\ \text{M=molarity}\\ \\ \text{V=volume}\\ \text{Molarity(M)=}\frac{\text{moles}}{\text{L}}\end{array}$

pH definition:

The concentration of hydrogen ion is measured using $\text{pH}$ scale.  The acidity of aqueous solution is expressed by $\text{pH}$ scale.

The $\text{pH}$ of a solution is defined as the negative logarithm of the hydrogen or hydronium ion concentration.

$\text{pH = -log}\left[{\text{H}}^{\text{+}}\right]$