Organic Chemistry
7th Edition
ISBN: 9780321803221
Author: Paula Y. Bruice
Publisher: Prentice Hall
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Chapter 21, Problem 37P
Interpretation Introduction
Interpretation:
The product obtained from the reaction of D-ribose with one equivalent of methanol and
Concept Introduction:
The hydroxyl group of anomeric carbon is protonated by an acid. The lone pair on the ring helps in eliminating a molecule of water which results in the formation of oxocarbenium ion. It is planar molecule. When the alcohol approaches from the top of the plane, the
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A hexose can be formed by reacting a pentose with Br2, H2O, and then Fe2(SO4)3.
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Draw the products formed when ß-D-galactose is treated with each reagent.a. Ag2O + CH3Ib. NaH + C6H5CH2Clc. The product in (b), then H3O+d. Ac2O + pyridinee. C6H5COCl + pyridinef. The product in (c), then C6H5COCl + pyridine
Chapter 21 Solutions
Organic Chemistry
Ch. 21.1 - Prob. 1PCh. 21.2 - Prob. 2PCh. 21.2 - Prob. 3PCh. 21.3 - Prob. 4PCh. 21.3 - Prob. 5PCh. 21.3 - Prob. 6PCh. 21.4 - Prob. 7PCh. 21.4 - Prob. 8PCh. 21.5 - Prob. 9PCh. 21.5 - Prob. 10P
Ch. 21.5 - Prob. 11PCh. 21.6 - Prob. 12PCh. 21.6 - Prob. 13PCh. 21.6 - Prob. 14PCh. 21.7 - Prob. 15PCh. 21.8 - Prob. 16PCh. 21.9 - Prob. 18PCh. 21.10 - Prob. 20PCh. 21.10 - Prob. 21PCh. 21.10 - Prob. 22PCh. 21.11 - Prob. 24PCh. 21.11 - Prob. 25PCh. 21.15 - Prob. 27PCh. 21.16 - Prob. 28PCh. 21.17 - Prob. 29PCh. 21.18 - Refer to Figure 20.5 to answer the following...Ch. 21 - Prob. 31PCh. 21 - Prob. 32PCh. 21 - Prob. 33PCh. 21 - Prob. 34PCh. 21 - Prob. 35PCh. 21 - Prob. 36PCh. 21 - Prob. 37PCh. 21 - Prob. 38PCh. 21 - Prob. 39PCh. 21 - Prob. 40PCh. 21 - Prob. 41PCh. 21 - Prob. 42PCh. 21 - Prob. 43PCh. 21 - Prob. 44PCh. 21 - The 1H NMR spectrum of D-glucose in D2O exhibits...Ch. 21 - Prob. 46PCh. 21 - Prob. 47PCh. 21 - Prob. 48PCh. 21 - Prob. 49PCh. 21 - Prob. 50PCh. 21 - Prob. 51PCh. 21 - Prob. 52PCh. 21 - Prob. 53PCh. 21 - Prob. 54PCh. 21 - Prob. 55PCh. 21 - A hexose is obtained when the residue of a shrub...Ch. 21 - Prob. 57PCh. 21 - Prob. 58PCh. 21 - Prob. 59PCh. 21 - Prob. 60PCh. 21 - Prob. 61PCh. 21 - Prob. 62PCh. 21 - Prob. 63PCh. 21 - Prob. 64PCh. 21 - Prob. 65PCh. 21 - Prob. 66P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Draw the product resulting from the Molisch reaction with D-xylose.arrow_forwardDraw the products formed when β-D-galactose is treated with each reagent. a. Ag2O + CH3I b. NaH + C6H5CH2Cl c. The product in (b), then H3O+ d. Ac2O + pyridine e. C6H5COCl + pyridine f. The product in (c), then C6H5COCl + pyridinearrow_forwardFructose in its bβ - D - pyranose form accounts for the powerful sweetness of honey. The β - D - furanose form, although sweet, is not as sweet as the pyranose form. The furanose form is the more stable form. Draw the two forms and explain why it may not always be wise to cook with honey.arrow_forward
- Draw the products formed when α-D-galactose is treated with each reagent: i. CH3I (excess), Ag2O ii. CH3OH, H3O+ iii. NaOH, H2O iv. Br2, H2Oarrow_forwardDraw the structure of a disaccharide formed from two mannose units joined by a 1->4-a-glycosidic linkage.arrow_forwardPredict the products obtained when d-galactose reacts with each reagent.(a) Br2 and H2Oarrow_forward
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