Concept explainers
Interpretation:
To calculate the equilibrium constant for the given reaction and explain why the given reaction is used in commercial isolation of magnesium from sea water.
Concept introduction:
The equilibrium constant is a quantity that relates the amount of product and reactant form at equilibrium at a given temperature. It is expressed as a ratio of molar concentrations of product over the reactants.
The equilibrium constant for any reaction is the reciprocal of the solubility product of that reaction. The solubility product is expressed by the symbol
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Chapter 21 Solutions
OWLv2 6-Months Printed Access Card for Kotz/Treichel/Townsend's Chemistry & Chemical Reactivity, 9th, 9th Edition
- A constant current of 1.25 amp is passed through an electrolytic cell containing a 0.050 M solution of CuSO4 and a copper anode and a platinum cathode until 3.00 g of copper is deposited. a How long does the current flow to obtain this deposit? b What mass of silver would be deposited in a similar cell containing 0.15 M Ag+ if the same amount of current were used?arrow_forwardAnswer the following questions by referring to standard electrode potentials at 25C. a Will oxygen, O2, oxidize iron(II) ion in solution under standard conditions? b Will copper metal reduce 1.0 M Ni2(aq) to metallic nickel?arrow_forwardCopper(I) ion disproportionates to copper metal and copper(ll) ion. (See Study Question 99.) 2 Cu+(aq) Cu(s) + Cu2 + (aq) (a) What two half-reactions make up the disproportionation reaction? (b) Use values of the standard reduction potentials for the two half-reactions in part (a) to determine whether this disproportionation reaction is product-favored at equilibrium. (c) What is the equilibrium constant for this reaction? If you have a solution that initially contains 0.10 mol of Cu+ in 1.0 L of water, what are the concentrations of Cu+ and Cu2+ at equilibrium?arrow_forward
- An electrochemical cell is made by placing an iron electrode in 1.00 L of 0.15 M FeSO4 solution and a copper electrode in 1.00 L of 0.040 M CuSO4 solution. a What is the initial voltage of this cell when it is properly constructed? b Calculate the final concentration of Cu2+ in this cell if it is allowed to produce an average current of l.25 amp for 375 s.arrow_forwardUse electrode potentials to answer the following questions, assuming standard conditions. a Do you expect permanganate ion (MnO4 ) to oxidize chloride ion to chlorine gas in acidic solution? b Will dichromate ion (Cr2O72) oxidize chloride ion to chlorine gas in acidic solution?arrow_forwardAn electrode is prepared from liquid mercury in contact with a saturated solution of mercury(I) chloride, Hg2Cl, containing 1.00 M Cl . The cell potential of the voltaic cell constructed by connecting this electrode as the cathode to the standard hydrogen half-cell as the anode is 0.268 V. What is the solubility product of mercury(I) chloride?arrow_forward
- An electrochemical cell consists of a standard hydrogen electrode and a copper metal electrode. If the copper electrode is placed in a solution of 0.10 M NaOH that is saturated with Cu(OH)2, what is the cell potential at 25C? [For Cu(OH)2, Ksp = 1.6 1019.]arrow_forwardA 1.0-L sample of 1.0 M HCl solution has a 10.0 A current applied for 45 minutes. What is the pH of the solution after the electricity has been turned off?arrow_forwardA galvanic cell is based on the following half-reactions: In this cell, the silver compartment contains a silver electrode and excess AgCl(s) (Ksp = 1.6 1010), and the copper compartment contains a copper electrode and [Cu2+] = 2.0 M. a. Calculate the potential for this cell at 25C. b. Assuming 1.0 L of 2.0 M Cu2+ in the copper compartment, calculate the moles of NH3 that would have to be added to give a cell potential of 0.52 Vat 25C (assume no volume change on addition of NH3). Cu2+(aq)+4NH3(aq)Cu(NH3)42+(aq)K=1.01013arrow_forward
- An electrode is prepared by dipping a silver strip into a solution saturated with silver thiocyanate, AgSCN, and containing 0.10 M SCN . The cell potential of the voltaic cell constructed by connecting this electrode as the cathode to the standard hydrogen half-cell as the anode is 0.45 V. What is the solubility product of silver thiocyanate?arrow_forwardAn electrochemical cell consists of a nickel metal electrode immersed in a solution with [Ni2+] = 1.0 M separated by a porous disk from an aluminum metal electrode immersed in a solution with [Al3+] = 1.0 M. Sodium hydroxide is added to the aluminum compartment, causing Al(OH)3(s) to precipitate. After precipitation of Al(OH)3 has ceased, the concentration of OH is 1.0 104 M and the measured cell potential is 1.82 V. Calculate the Ksp value for Al(OH)3. Al(OH)3(s)Al3+(aq)+3OH(aq)Ksp=?arrow_forward
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