Answer Answer is 101 Explanation Given Information Calculation : 1 + 100 = 101 2 + 99 = 101 3 + 98 = 101 (b) To determine To calculate : Number of pairs Answer The answer is 100 Explanation Given Information Calculation : There are 100 pairs ( 1 , 100 ) , ( 2 , 99 ) ............ ( 100 , 1 ) (c) To determine To calculate : 2S = ? , if S = Sum of integers from 1 to 100 Answer The answer is 10100 Explanation Given Information Calculation : 2 S = 101 × 100 2 S = 10100 (d) To determine To calculate : Sum of integer through 1 to 100 ? Explain. Answer The final answer is 5050 Explanation Given Information Calculation : 2 S = 10100 S = 5050 So Sum of integers through 1 to 100 = 5050 .

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Concept explainers

Statements and Logic

Logic is the analysis of general patterns of thoughts without regard to any specific sense of context.

Videos

Question

Chapter 2.1, Problem 52E

To determine

To calculate: Sum of number in each pair?

Expert Solution

Answer to Problem 52E

Answer is 101

Explanation of Solution

Given Information

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.1, Problem 52E , additional homework tip 2

Calculation:

1+100=101

2+99=101

3+98=101

(b)

To determine

To calculate:

Number of pairs

(b)

Expert Solution

Answer to Problem 52E

The answer is 100

Explanation of Solution

Given Information

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.1, Problem 52E , additional homework tip 3

Calculation:

There are 100 pairs

(1, 100),(2, 99)............(100,1)

(c)

To determine

To calculate: 2S = ? , if S = Sum of integers from 1 to 100

(c)

Expert Solution

Answer to Problem 52E

The answer is 10100

Explanation of Solution

Given Information

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.1, Problem 52E , additional homework tip 5

Calculation:

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.1, Problem 52E , additional homework tip 6

2S=101×100

2S=10100

(d)

To determine

To calculate:

Sum of integer through 1 to 100 ? Explain.

(d)

Expert Solution

Answer to Problem 52E

The final answer is 5050

Explanation of Solution

Given Information

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.1, Problem 52E , additional homework tip 8

Calculation:

2S=10100

S=5050

Sum of integers through 1 to 100

=5050 .

Chapter 2.1, Problem 51E

Chapter 2.1, Problem 53E

Chapter 2 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 2.1 - Prob. 1PSQ Ch. 2.1 - Prob. 2PSQ Ch. 2.1 - Prob. 3PSQ Ch. 2.1 - Prob. 4PSQ Ch. 2.1 - Prob. 5PSQ Ch. 2.1 - Prob. 6PSQ Ch. 2.1 - Prob. 7PSQ Ch. 2.1 - Prob. 8PSQ Ch. 2.1 - Prob. 9PSQ Ch. 2.1 - Prob. 10PSQ

Ch. 2.1 - Prob. 11PSQ Ch. 2.1 - Prob. 1C Ch. 2.1 - Prob. 2C Ch. 2.1 - Prob. 3C Ch. 2.1 - Prob. 4C Ch. 2.1 - Prob. 5C Ch. 2.1 - Prob. 6C Ch. 2.1 - Prob. 7C Ch. 2.1 - Prob. 8C Ch. 2.1 - Prob. 9C Ch. 2.1 - Prob. 10C Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - Prob. 61E Ch. 2.1 - Prob. 62E Ch. 2.1 - Prob. 63E Ch. 2.1 - Prob. 64E Ch. 2.1 - Prob. 65E Ch. 2.2 - Prob. 1C Ch. 2.2 - Prob. 2C Ch. 2.2 - Prob. 3C Ch. 2.2 - Prob. 4C Ch. 2.2 - Prob. 5C Ch. 2.2 - Prob. 6C Ch. 2.2 - Prob. 7C Ch. 2.2 - Prob. 8C Ch. 2.2 - Prob. 9C Ch. 2.2 - Prob. 10C Ch. 2.2 - Prob. 11C Ch. 2.2 - Prob. 12C Ch. 2.2 - Prob. 1E Ch. 2.2 - Prob. 2E Ch. 2.2 - Prob. 3E Ch. 2.2 - Prob. 4E Ch. 2.2 - Prob. 5E Ch. 2.2 - Prob. 6E Ch. 2.2 - Prob. 7E Ch. 2.2 - Prob. 8E Ch. 2.2 - Prob. 9E Ch. 2.2 - Prob. 10E Ch. 2.2 - Prob. 11E Ch. 2.2 - Prob. 12E Ch. 2.2 - Prob. 13E Ch. 2.2 - Prob. 14E Ch. 2.2 - 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Prob. 5C Ch. 2.7 - Prob. 6C Ch. 2.7 - Prob. 7C Ch. 2.7 - Prob. 8C Ch. 2.7 - Prob. 9C Ch. 2.7 - Prob. 10C Ch. 2.7 - Prob. 11C Ch. 2.7 - Prob. 12C Ch. 2.7 - Prob. 13C Ch. 2.7 - Prob. 14C Ch. 2.7 - Prob. 15C Ch. 2.7 - Prob. 16C Ch. 2.7 - Prob. 17C Ch. 2.7 - Prob. 18C Ch. 2.7 - Prob. 1E Ch. 2.7 - Prob. 2E Ch. 2.7 - Prob. 3E Ch. 2.7 - Prob. 4E Ch. 2.7 - Prob. 5E Ch. 2.7 - Prob. 6E Ch. 2.7 - Prob. 7E Ch. 2.7 - Prob. 8E Ch. 2.7 - Prob. 9E Ch. 2.7 - Prob. 10E Ch. 2.7 - Prob. 11E Ch. 2.7 - Prob. 12E Ch. 2.7 - Prob. 13E Ch. 2.7 - Prob. 14E Ch. 2.7 - Prob. 15E Ch. 2.7 - Prob. 16E Ch. 2.7 - Prob. 17E Ch. 2.7 - Prob. 18E Ch. 2.7 - Prob. 19E Ch. 2.7 - Prob. 20E Ch. 2.7 - Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.7 - Prob. 46E Ch. 2.7 - Prob. 47E Ch. 2.7 - Prob. 48E Ch. 2.7 - Prob. 49E Ch. 2.7 - Prob. 50E Ch. 2.7 - Prob. 51E Ch. 2.7 - Prob. 52E Ch. 2.7 - Prob. 53E Ch. 2.7 - Prob. 54E Ch. 2.7 - Prob. 55E Ch. 2.7 - Prob. 56E Ch. 2 - Prob. 1MCQ Ch. 2 - Prob. 2MCQ Ch. 2 - Prob. 3MCQ Ch. 2 - Prob. 4MCQ Ch. 2 - Prob. 5MCQ Ch. 2 - Prob. 6MCQ Ch. 2 - Prob. 7MCQ Ch. 2 - Prob. 8MCQ Ch. 2 - Prob. 9MCQ Ch. 2 - Prob. 10MCQ Ch. 2 - Prob. 11MCQ Ch. 2 - Prob. 12MCQ Ch. 2 - Prob. 13MCQ Ch. 2 - Prob. 14MCQ Ch. 2 - Prob. 15MCQ Ch. 2 - Prob. 16MCQ Ch. 2 - Prob. 17MCQ Ch. 2 - Prob. 18MCQ Ch. 2 - Prob. 19MCQ Ch. 2 - Prob. 20MCQ Ch. 2 - Prob. 21MCQ Ch. 2 - Prob. 22MCQ Ch. 2 - Prob. 1CR Ch. 2 - Prob. 2CR Ch. 2 - Prob. 3CR Ch. 2 - Prob. 4CR Ch. 2 - Prob. 5CR Ch. 2 - Prob. 6CR Ch. 2 - Prob. 7CR Ch. 2 - Prob. 8CR Ch. 2 - Prob. 9CR Ch. 2 - Prob. 10CR Ch. 2 - Prob. 11CR Ch. 2 - 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Sum of number in each pair?

Concept explainers

Videos

To calculate: Sum of number in each pair?

Answer to Problem 52E

Explanation of Solution

To calculate: Number of pairs

Answer to Problem 52E

Explanation of Solution

To calculate: 2S = ? , if S = Sum of integers from 1 to 100

Answer to Problem 52E

Explanation of Solution

To calculate: Sum of integer through 1 to 100 ? Explain.

Answer to Problem 52E

Explanation of Solution

Chapter 2 Solutions

Additional Math Textbook Solutions

To calculate:

Number of pairs

To calculate:

Sum of integer through 1 to 100 ? Explain.