Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Percentage

A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.

Algebraic Expressions

In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.

Numbers

Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.

Subtraction

Before we begin to understand the subtraction of algebraic expressions, we need to list out a few things that form the basis of algebra.

Addition

Before we begin to understand the addition of algebraic expressions, we need to list out a few things that form the basis of algebra.

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Question

Chapter 2.2, Problem 50E

To determine

To Make: An expression for the width of the rectangular pen.

Expert Solution

Answer to Problem 50E

The expression is 250−x feet.

Explanation of Solution

Given Information:

The length of rectangular pen =x feet and 500 feet of fencing .

Formula:

perimeter = 2(length + width)

Calculation:

Let the width be w feet.

As 500 feet of fencing is to be used, so perimeter =500 feet

Thus by the formula for perimeter,

500=2(x+w)

Dividing by 2 on both sides,

250=x+w

Transposing

x to the left side,

250−x=w

Or w=250−x

To determine

To Make: An expression for the area of the rectangular pen.

Expert Solution

Answer to Problem 50E

The expression for the area is 250−x2 square feet.

Explanation of Solution

Given Information:

The length of the rectangular pen =x feet

Formula used:

area=length×breadth

Calculation:

For length =x feet

Width

=250−x , as found in part (a)

So area is given by

A=x(250−x) square feet,

This implies, by distributive property

A=250−x.x square feet

Or 250−x2

To determine

To Evaluate: The width and area of rectangular pen.

Expert Solution

Answer to Problem 50E

The width is 90 feet and area is 14,400 square feet.

Explanation of Solution

Given Information:

The length of the rectangular pen 160 feet

Calculation:

As found in part (a) and part (b),

Width

=250−x , and area =250−x2 square feet.

Whose length is x feet.

Replacing x by 160 ,

Width

=(250−160) feet =90 feet, and

Area =(250×160−(160)2) square feet

=14,400 square feet

Chapter 2.2, Problem 49E

Chapter 2.2, Problem 51E

Chapter 2 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 2.1 - Prob. 1PSQ Ch. 2.1 - Prob. 2PSQ Ch. 2.1 - Prob. 3PSQ Ch. 2.1 - Prob. 4PSQ Ch. 2.1 - Prob. 5PSQ Ch. 2.1 - Prob. 6PSQ Ch. 2.1 - Prob. 7PSQ Ch. 2.1 - Prob. 8PSQ Ch. 2.1 - Prob. 9PSQ Ch. 2.1 - Prob. 10PSQ

Ch. 2.1 - Prob. 11PSQ Ch. 2.1 - Prob. 1C Ch. 2.1 - Prob. 2C Ch. 2.1 - Prob. 3C Ch. 2.1 - Prob. 4C Ch. 2.1 - Prob. 5C Ch. 2.1 - Prob. 6C Ch. 2.1 - Prob. 7C Ch. 2.1 - Prob. 8C Ch. 2.1 - Prob. 9C Ch. 2.1 - Prob. 10C Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - 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