- a)
Interpretation: The equilibrium constant is calculated and the reason for the
Concept Introduction:
Equilibrium constant: The equilibrium constant of a
Gibb’s free energy: The Gibb’s free energy also termed as the available energy; is the
To Identify: The equilibrium constant is calculated
- b)
Interpretation: The equilibrium constant is calculated and the reason for the
Concept Introduction:
Equilibrium constant: The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium.
Gibb’s free energy: The Gibb’s free energy also termed as the available energy; is the thermodynamic potential that is minimized when a system reaches chemical equilibrium at constant and temperature.
To explain the reason for insoluble
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CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
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- The following data were collected for the reaction, H2(g) + L(g) ** - HI(g), at equilibrium at 25°C: [HJ = 0.10 mol L-1, [IJ = 0.20 mol L"\ [HI] = 4.0 mol L’1 Calculate the equilibrium constant for the reaction at this temperature.arrow_forwardUse electrode potentials to answer the following questions, assuming standard conditions. a Do you expect permanganate ion (MnO4 ) to oxidize chloride ion to chlorine gas in acidic solution? b Will dichromate ion (Cr2O72) oxidize chloride ion to chlorine gas in acidic solution?arrow_forwardThe following reactions all occur in a blast furnace. Which of these are redox reactions? (a) 3Fe2O3(s)+CO(g)2Fe3O4(s)+CO2(g) (b) Fe3O4(s)+CO(g)3FeO(s)+CO2(g) (c) FeO(s)+CO(g)Fe(l)+CO2(g) (d) C(s)+O2(g)CO2(g) (e) C(s)+CO2(g)2CO(g) (f) CaCO3(s)CaO(s)+CO2(g) (g) CaO(s)+SiO2(s)CaSiO3(l)arrow_forward
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