(a) Interpretation: The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined: Pt|Cr 3+ (2 .00×10 -4 M),Cr 2+ (1 .50×10 -3 M)||Pb 2+ (5 .60×10 -2 M)Pb Concept introduction: The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213
BuyFind

Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

Solutions

Chapter 22, Problem 22.7QAP
Interpretation Introduction

(a)

Interpretation:

The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined:

Pt|Cr3+(2.00×10-4 M),Cr2+(1.50×10-3 M)||Pb2+(5.60×10-2 M)Pb

Concept introduction:

The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

Interpretation Introduction

(b)

Interpretation:

The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined:

Hg|Hg22+(2.00×10-2 M)||H+(1.50×10-2 M),V(2.00×10-2 M),VO2+(3.0×10-3 M)|Pt

Concept introduction:

The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

Interpretation Introduction

(c)

Interpretation:

The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined:

Pt|Fe3+(3.00×10-2 M),Fe2+(4.00×10-5 M)||Sn2+(3.5×10-2 M),Sn4+(5.50×10-4 M)|Pt

Concept introduction:

The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

Want to see the full answer?

Check out a sample textbook solution.

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

*Response times may vary by subject and question complexity. Median response time is 34 minutes for paid subscribers and may be longer for promotional offers.