# (a) Interpretation: The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined: Pt|Cr 3+ (2 .00×10 -4 M),Cr 2+ (1 .50×10 -3 M)||Pb 2+ (5 .60×10 -2 M)Pb Concept introduction: The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution. ### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213 ### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

#### Solutions

Chapter 22, Problem 22.7QAP
Interpretation Introduction

## (a)Interpretation:The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined:Pt|Cr3+(2.00×10-4 M),Cr2+(1.50×10-3 M)||Pb2+(5.60×10-2 M)PbConcept introduction:The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

Interpretation Introduction

### (b)Interpretation:The theoretical potential of the following cell and whether the direction of the cell reaction spontaneous as written or spontaneous in the opposite direction should be determined:Hg|Hg22+(2.00×10-2 M)||H+(1.50×10-2 M),V(2.00×10-2 M),VO2+(3.0×10-3 M)|PtConcept introduction:The electrode potential of the cell is the difference of potential difference of two electrodes. Here, the electrode potential of the cell is potential difference of electrode and solution.

Interpretation Introduction

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