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CALCULUS+ITS APPL..-MYLAB ACCESS
- YOUR TURN Find an equation of the curve whose tangent line has slope f(x)=3x1/2+4 and passes through the point (1,2).arrow_forwardThe graph of the function f(x) is shown below. It consists of a semicircle and two straight line segments. 50 -3 -2 y 3 2 -1 1 2 (a) Which of the following numbers is the largest: f'(-3.95), ƒ' (-1.5), ƒ' (-0.05), ƒ' (1), ƒ' (3.05)? 3 4 5 Xarrow_forwardUse the given graph of y = f(x) to evaluate the following. (a) f(-3) (b) f(2) (c) f- (0) (d) f-1(-3) 1y=x 40 अ ओ ..... (a) f(- 3) =| (b) f(2) = (c)f-*(0) =D (4) 1^(- 3)= .....arrow_forward
- and Find f(x). f(x) = 3x5 (x² - 4) f'(x) = Question 2, 3.3.9 چارarrow_forwardThe graph of y = f(x) passes through the points (0, 1), (1, 2), and (2, 3). Find the corresponding points on the graph of y = f(x + 3) − 2. (0,1) --> (1,2) --> (2,3) -->arrow_forwardgraph f’(x) on this graph of f(x)?arrow_forward
- What does the f'(x) graph look likearrow_forwardUse the graph of y = f(x) to identify at which of the indicated points f'(x) changes from positive to negative, changes from negative to positive, and does not change sign. y (-1, 5) (-3, 2) (2, 1) X -2 -2 (a) f'(x) changes from positive to negative O (-3, 2) O (-1, 5) О (2, 1) None of these points represents a change in f'(x) from positive to negative. (b) f'(x) changes from negative to positive O (-3, 2) O (-1, 5) O (2, 1) O None of these points represents a change in f'(x) from negative to positive. (c) f'(x) does not change sign (-3, 2) (-1, 5) (2, 1)arrow_forwardSuppose that the function y=f(x) is increasing on the interval (-1,5). Over what interval is the graph of y=f(x-5) increasing ?arrow_forward
- Calculus For The Life SciencesCalculusISBN:9780321964038Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.Publisher:Pearson Addison Wesley,Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillCollege AlgebraAlgebraISBN:9781305115545Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning