Finding an Equation of a Tangent Line In Exercises 45-50, (a) find an equation of the tangent line to the graph of the function at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the tangent feature of a graphing utility to confirm your results. See Example 10. y = 3 x ( x 2 − 2 x ) ; ( 2 , 18 )
Finding an Equation of a Tangent Line In Exercises 45-50, (a) find an equation of the tangent line to the graph of the function at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the tangent feature of a graphing utility to confirm your results. See Example 10. y = 3 x ( x 2 − 2 x ) ; ( 2 , 18 )
Finding an Equation of a Tangent Line In Exercises 45-50, (a) find an equation of the tangent line to the graph of the function at the given point, (b) use a graphing utility to graph the function and its tangent line at the point, and (c) use the tangent feature of a graphing utility to confirm your results. See Example 10.
Sketch graphs, marking major points of interest. y = (x-1)(x-2)(x-4)y = (x+1)/(x-3)
A long jumper leaves the ground at an angle of 20° above the horizontal, at a speed of 9 m/s. The height of the jumper can be modeled by
h(x) = -0.048x²+
+0.364.x, where h is the jumper's height in meters and x is the horizontal distance from the point of launch.
Part: 0 / 3
Part 1 of 3
(a) At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places.
The long jumper reaches a maximum height when the horizontal distance from the point of launch is approximately
meters.
X
Find the x and y intercepts of the graph of f(x)
(Show step by step solutions )
Chapter 2 Solutions
Bundle: Calculus: An Applied Approach, Brief, Loose-leaf Version, 10th + WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term
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Differential Equation | MIT 18.01SC Single Variable Calculus, Fall 2010; Author: MIT OpenCourseWare;https://www.youtube.com/watch?v=HaOHUfymsuk;License: Standard YouTube License, CC-BY