Conversion of bromide compound into alkene compound has to be done via Hofmann elimination. Concept Introduction : The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes . Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene. If the starting material contains one less carbon skeleton than the product, S N 2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material. To find: Conversion of bromide compound into alkene compound Formation of cyanide by S N 2 nucleophilic reaction

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Answer 1

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Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

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Answer 2

Question

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

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Answer 3

Question

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

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Answer 4

Question

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

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Answer 5

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

Answer 6

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

Answer 7

Chapter 22, Problem 85IP

Interpretation Introduction

Interpretation: Conversion of bromide compound into alkene compound has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are used as the reaction conditions for the given reactions. This reaction is called Hofmann elimination. The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternaryammonium salt which is aexcellent leaving group. After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes. Alkene formation involves in E2 elimination. Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

If the starting material contains one less carbon skeleton than the product, S_N2 nuclophilic addition of cyanide ion on starting material is proceeded. The resulting nitrile is then reduced by lithium aluminum hydride with water as work-up process. Now, the product contains one extra carbon skeleton than the starting material.

To find: Conversion of bromide compound into alkene compound

Formation of cyanide by S_N2 nucleophilic reaction

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.2 - Prob. 3ATS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC

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Chapter 22 Solutions