Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Question
Chapter 22, Problem 9P
(a)
To determine
To determine the direction of the electric field inside the shell.
(b)
To determine
The electric field in between the region of radius
(c)
To determine
The electric field outside the shell.
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Calculate the electric field of l = 40 m wire that has a charge density of 1 =5.4
nC/m at a distance of z = 6.7 cm above the midpoint of the wire.
Round your answer to the nearest whole number.
Your Answer:
Answer
A ring-shaped conductor with radius a = 2.70 cm has a total
positive charge Q = 0.125 nC uniformly distributed around it.
(Figure 1)
For related problem-solving tips and strategies, you may want
to view a Video Tutor Solution of Field of a ring of charge.
Figure
dQ
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X
dE
dE
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1 of 1
dE
X
SET UP: Q = 0.125 × 10-⁹ C, a = 0.027 m and x = 0.430 m.
1
Qx
EXECUTE: E
Απεο (22+a2)3/2°
Part B
+x-direction
-x-direction
What is the direction of the electric field at point P?
Submit
Previous Answers
Correct
Part C
·î ·
=
|VD | ΑΣΦ
F = 1.7910-5
(6.04 N/C)i.
A particle with a charge of - 2.40 μC is placed at the point P described in part A. What is the magnitude of the force exerted by the particle on the
ring?
Express your answer in newtons.
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?
Review | Constants
N
Human nerve cells have a net negative charge and the material in the interior of the cell is agood conductor. If a cell has a net charge of -8.65 pC (picocoulomb)what are the magnitudeand direction (inward or outward) of the net flux through the cell boundary? use GRESA method.
Chapter 22 Solutions
Physics for Scientists and Engineers
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