ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 
ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 
3rd Edition
ISBN: 9781119815792
Author: Klein
Publisher: WILEY
Question
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Chapter 22.6, Problem 14PTS

(a)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  1

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  2

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  3

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(b)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  4

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  5

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  6

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(c)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  7

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  8

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  9

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(d)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  10

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  11

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  12

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

(e)

Interpretation Introduction

Interpretation: For a given set of compounds, amines are to be prepared via two different methods of reductive amination

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride.  It reduces the carbonyl group into amine group in a rapid way.  So, it is called as reductive amination reactions.  Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  13

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  14

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S , Chapter 22.6, Problem 14PTS , additional homework tip  15

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds.  After the cleavage, retrosynthetic analysis of the starting materials is done.  If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

Blurred answer

Chapter 22 Solutions

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 

Ch. 22.4 - Prob. 10CCCh. 22.4 - Prob. 11CCCh. 22.5 - Prob. 2LTSCh. 22.5 - Prob. 12PTSCh. 22.5 - Prob. 13ATSCh. 22.6 - Prob. 3LTSCh. 22.6 - Prob. 14PTSCh. 22.6 - Prob. 15ATSCh. 22.7 - Prob. 4LTSCh. 22.7 - Prob. 16PTSCh. 22.7 - Prob. 17PTSCh. 22.7 - Prob. 18PTSCh. 22.7 - Prob. 19ATSCh. 22.8 - Prob. 20CCCh. 22.8 - Prob. 21CCCh. 22.8 - Prob. 22CCCh. 22.9 - Prob. 5LTSCh. 22.9 - Prob. 23PTSCh. 22.9 - Prob. 24ATSCh. 22.10 - Prob. 25CCCh. 22.11 - Prob. 26CCCh. 22.11 - Prob. 6LTSCh. 22.11 - Prob. 27PTSCh. 22.11 - Prob. 28ATSCh. 22.12 - Prob. 29CCCh. 22.12 - Prob. 30CCCh. 22.13 - Prob. 31CCCh. 22.13 - Prob. 32CCCh. 22 - Prob. 33PPCh. 22 - Prob. 34PPCh. 22 - Prob. 35PPCh. 22 - Prob. 36PPCh. 22 - Prob. 37PPCh. 22 - Prob. 38PPCh. 22 - Prob. 39PPCh. 22 - Prob. 40PPCh. 22 - Prob. 41PPCh. 22 - Prob. 42PPCh. 22 - Prob. 43PPCh. 22 - Prob. 44PPCh. 22 - Prob. 45PPCh. 22 - Prob. 46PPCh. 22 - Prob. 47PPCh. 22 - Prob. 48PPCh. 22 - Prob. 49PPCh. 22 - Prob. 50PPCh. 22 - Prob. 51PPCh. 22 - Prob. 52PPCh. 22 - Prob. 53PPCh. 22 - Prob. 54PPCh. 22 - Prob. 55PPCh. 22 - Prob. 56PPCh. 22 - Prob. 57PPCh. 22 - Prob. 58PPCh. 22 - Prob. 59PPCh. 22 - Prob. 60PPCh. 22 - Prob. 61PPCh. 22 - Prob. 62PPCh. 22 - Prob. 63PPCh. 22 - Prob. 64PPCh. 22 - Prob. 65PPCh. 22 - Prob. 66PPCh. 22 - Prob. 67PPCh. 22 - Prob. 68PPCh. 22 - Prob. 69PPCh. 22 - Prob. 70PPCh. 22 - Prob. 71PPCh. 22 - Prob. 72PPCh. 22 - Prob. 73IPCh. 22 - Prob. 74IPCh. 22 - Prob. 75IPCh. 22 - Prob. 76IPCh. 22 - Prob. 77IPCh. 22 - Prob. 78IPCh. 22 - Prob. 79IPCh. 22 - Prob. 80IPCh. 22 - Prob. 81IPCh. 22 - Prob. 82IPCh. 22 - Prob. 83IPCh. 22 - Prob. 84IPCh. 22 - Prob. 85IPCh. 22 - Prob. 86IPCh. 22 - Prob. 87IPCh. 22 - Prob. 88IPCh. 22 - Prob. 89IPCh. 22 - Prob. 90IPCh. 22 - Prob. 91IPCh. 22 - Prob. 92IPCh. 22 - Prob. 93IPCh. 22 - Prob. 94IPCh. 22 - Prob. 95IPCh. 22 - Prob. 96CPCh. 22 - Prob. 97CPCh. 22 - Prob. 98CPCh. 22 - Prob. 99CP
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