(a) The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Question

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Answer 1

Question

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

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Answer 2

Question

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

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Answer 3

Question

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

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Answer 4

Question

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

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Answer 5

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

Answer 6

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

Answer 7

Chapter 23, Problem 104QAP

To determine

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Answer 8

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=1.1×10−3 rad

2ⁿ^d smallest angle = θ2=2.2×10−3 rad

3^r^d smallest angle = θ3=3.3×10−3 rad

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

Wavelength of light = λ=550 nm = 5.50 ×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Following equation satisfy for the diffraction of single slit,

w sinθ=mλ

Calculation:

Since, w is very small to λ, so, θ would be very small.

In this situation, we can apply the following approximation,

sinθ≈θ=mλw

Now, let's plug all values in above equation,

θ=mλw=m(5.50× 10 −7m)0.5× 10 −3m=m(1.1× 10 −3 rad)now, when m = 1,θ1=1.1×10−3 radwhen m = 2,θ2=2.2×10−3 radWhen m = 3,θ3=3.3×10−3 rad

Conclusion:

So, the three smallest angles on the either side of central maximum at which no light will reach the cat's retina and medium inside the eye ball is air are 1.1×10−3 rad, 2.2×10−3 rad, 3.3×10−3 rad.

Answer 13

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

Answer 14

To determine

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Answer 15

Expert Solution

Answer to Problem 104QAP

1^s^t smallest angle = θ1=7.86×10−4 rad

2ⁿ^d smallest angle = θ2=1.57×10−3 rad

3^r^d smallest angle = θ3=2.36×10−3 rad

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

Refractive index fluid that is in the eyeball,

n=1.4

Wavelength of light in air = λ=550 nm = 5.50×10−7m

Width of slit = w=0.500 mm=0.5×10−3m

Formula used:

Wavelength of light in medium is written as,

λ'=λnλ'= wavelength of light in mediumλ=wavelength of light in airn = refractive index

Calculation:

Wavelength of light in fluid,

λ'=λn=5.50×10−7m1.4=3.929×10−7m

Now, from above formula,

w sinθ=mλ'sinθ≈θ=mλ'w

Let's plug all values,

θ=mλ'w=m(3.929× 10 −7m)0.5× 10 −3mθ=m(7.857×10−4rad)now, if m = 1,θ1=7.857×10−4radif m = 2,θ2=1.57×10−3 radif m = 3,θ3=2.36×10−3rad

Conclusion:

Thus, the three smallest angles on either side of retina of cat's eye when eyeball is filled with fluid having refractive index n=1.4 are 7.86×10−4 rad,1.57×10−3 rad and 2.36×10−3 rad.

Answer 20

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

Answer 21

To determine

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Answer 22

Expert Solution

Answer to Problem 104QAP

Cat cannot distinguish the location of fringe on the retina.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

From above discussion, we can see that angle of diffraction of light on either side of central bright spot of the retina is very small. So, location of bright and dark fringes would be very close to each other. Cat's eye has no ability to perceive that order of fringes. So, cat would perceive it as continuous bright light not as alternate dark and bright that occurs due to diffraction.

Conclusion:

Thus, cat would not see that alternate dark and bright fringes.

Answer 27

Ch. 23 - Prob. 1QAP Ch. 23 - Prob. 2QAP Ch. 23 - Prob. 3QAP Ch. 23 - Prob. 4QAP Ch. 23 - Prob. 5QAP Ch. 23 - Prob. 6QAP Ch. 23 - Prob. 7QAP Ch. 23 - Prob. 8QAP Ch. 23 - Prob. 9QAP Ch. 23 - Prob. 10QAP

(a) The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Concept explainers

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(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Answer to Problem 104QAP

Explanation of Solution

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Answer to Problem 104QAP

Explanation of Solution

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye

Answer to Problem 104QAP

Explanation of Solution

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Chapter 23 Solutions

(a) The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Concept explainers

Videos

(a) The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

Answer to Problem 104QAP

Explanation of Solution

(b) The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

Answer to Problem 104QAP

Explanation of Solution

(c) The explanation of the order of fringes due to diffraction of light by cat's eye

Answer to Problem 104QAP

Explanation of Solution

Want to see more full solutions like this?

Chapter 23 Solutions

(a)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with air.

(b)

The three smallest angles on the either side of central maximum at which no light will reach the cat's retina and it is assumed the eyeball of cat is filled with a liquid having refractive index 1.4.

(c)

The explanation of the order of fringes due to diffraction of light by cat's eye