General Chemistry
General Chemistry
11th Edition
ISBN: 9781305859142
Author: Ebbing, Darrell D., Gammon, Steven D.
Publisher: Cengage Learning,
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Chapter 23, Problem 23.24QP

In the models shown here, C atoms are black and H atoms are light blue:

Chapter 23, Problem 23.24QP, In the models shown here, C atoms are black and H atoms are light blue: a Write the molecular

  1. a Write the molecular formula of each molecule.
  2. b Write the condensed structural formula for each molecule.
  3. c Give the IUPAC name of each molecule.

 (a)

Expert Solution
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Interpretation Introduction

Interpretation:

Molecular formula for the given set of compounds has to be written.

Concept Introduction:

Molecular formula of a compound represents the total number of atoms that is present in it.  It does not give any other information about the functional group, etc present in the compound.  Simply it gives how many number of atoms are present for each element that is present in the compound.

To Write: The molecular formula for the given ball-stick models.

Answer to Problem 23.24QP

The molecular formula for the first structure is C4H8 and the name is 2-butene.

The molecular formula for the second structure is C6H12 and the name is cyclohexane.

The molecular formula for the third structure is C8H18 and the name is 2,2,4-trimethylpentane.

Explanation of Solution

For First structure:

In the given ball-stick model, the black spheres are carbon atoms, light blue spheres are hydrogen atoms and dark blue spheres are nitrogen atoms.  The total number of black spheres is 4, while that of light blue spheres is 8 and a double bond is present between the second and third carbon atom.  Hence we arrive at the molecular formula of C4H8 .

For Second structure:

In the given ball-stick model, the black spheres are carbon atoms, light blue spheres are hydrogen atoms and red spheres are oxygen atoms.  The total number of black spheres is 6, while that of light blue spheres is 12 and the given structure is a cyclic one.  Hence we arrive at the molecular formula of C6H12 .

For Third structure:

In the given ball-stick model, the black spheres are carbon atoms, light blue spheres are hydrogen atoms and red spheres are oxygen atoms.  The total number of black spheres is 8, while that of light blue spheres is 18.  Hence we arrive at the molecular formula of C8H18 .

Conclusion

The molecular formula for the given ball-stick model compounds are written.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Condensed structural formula for the given ball-stick model compounds has to be written.

Concept Introduction:

Condensed structural formula is representation of the organic compound.  In this the lengthy carbon chain is shown only with the carbon atoms (along with the hydrogen) without any bonds.  The additional branches are shown with explicit bonds.

To Write: The condensed structural formula for the given set of ball-stick model compounds.

Answer to Problem 23.24QP

The condensed structural formula of First structure is CH3CH=CHCH3 .

The condensed structural formula for the Second structure is,

General Chemistry, Chapter 23, Problem 23.24QP , additional homework tip  1

The condensed structural formula for the Third structure is,

General Chemistry, Chapter 23, Problem 23.24QP , additional homework tip  2

Explanation of Solution

For First structure:

Condensed structural formula can be drawn considering the carbon skeleton in the given ball-stick model.  From the ball-stick model we can find that there are four carbon atom present in it and a double bond is present between second and third carbon atom.  The single bonds alone are removed to obtain the condensed structural formula as shown below,

General Chemistry, Chapter 23, Problem 23.24QP , additional homework tip  3

For Second structure:

Condensed structural formula can be drawn considering the carbon skeleton in the given ball-stick model.  The carbon chain is drawn.  As this is a cyclic compound, the condensed structural formula can be drawn without removing the single bonds between the carbon atoms.

General Chemistry, Chapter 23, Problem 23.24QP , additional homework tip  4

For Third structure:

Condensed structural formula can be drawn considering the carbon skeleton in the given ball-stick model.  The carbon chain is drawn.  The second carbon atom is attached to two methyl groups and fourth carbon is substituted with one methyl group.  The single bonds are removed in the parent structure which results in the condensed structural formula as shown below,

General Chemistry, Chapter 23, Problem 23.24QP , additional homework tip  5

Conclusion

The condensed structural formula are written for the given ball-stick model representation of compounds.

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

IUPAC names has to be given for the given set of ball-stick model compounds.

Concept Introduction:

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

Root word represents the longest continuous carbon skeleton of the organic molecule.

To Give: The IUPAC name for the given ball-stick model compounds.

Answer to Problem 23.24QP

IUPAC name for the First structure is 2-butene.

IUPAC name for the Second structure is cyclohexane

IUPAC name for the Third structure is 2,2,4-trimethylpentane.

Explanation of Solution

For First structure:

From the given structure the lengthy carbon chain has to be identified.  In this case it is a four carbon chain and hence the parent alkane is butane.  A double bond is present between the second and third carbon atom.  Hence, the compound is named as butane.  The position of the double bond should be mentioned in IUPAC name, so that it should get least numbering.  Therefore, the name of the given hydrocarbon is written as 2-butene.

For Second structure:

From the given structure we can identify that it is a cyclic compound.  As there is no unsaturation present, the given compound is an alkane.  Total number of carbon atoms present in it is six.  Therefore, the parent hydrocarbon is hexane.  As it is a cyclic structure, “-cyclo” has to be added before.  Hence, the IUPAC name for the given compound is given as cyclohexane.

For Third structure:

From the given structure, we can see that the lengthy carbon chain consists of five carbon atoms.  Therefore, the parent hydrocarbon is pentane.  While looking into the structure, we can see that two methyl groups are substituted in second carbon atom and one methyl group is substituted in fourth carbon atom.  Hence, we can arrive at the IUPAC name as 2,2,4-trimethylpentane.

Conclusion

IUPAC name for each molecule was given.

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Chapter 23 Solutions

General Chemistry

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