Chapter 23, Problem 23.32P

Interpretation Introduction

Interpretation:

Value of ${\text{ΔG}}_{rxn}^o$ at $25°C$ has to be calculated and when a solution with $1.0\text{ M }C{a}^{2+}$ and $1.0\text{ M }C{O}_3^{2-}$ is prepared, then what will happen has to be given.

Concept Introduction:

The Gibbs free energy or the free energy change is a thermodynamic quantity represented by $\Delta G$. Value of $\Delta G_{rxn}^o$ is determined as follows,

  ${\text{ΔG}}_{rxn}^o=-\text{RT}\text{ln K}$

The formula of ${\text{ΔG}}_{\text{rxn}}$ in is given below,

    ${\text{ΔG}}_{rxn}=\text{RT}\text{ln }\left(\frac{{\text{Q}}_c}{K_c}\right)$

If $Q_c>{\text{ K}}_c$ then the reaction is spontanous in backward reaction (from right to left).

If $Q_c{\text{< K}}_c$ then the reaction is spontanous in forward reaction (from left to right).

If $Q_c={\text{ K}}_c$ then the reaction will be at equilibrium.