Chemistry: An Atoms-Focused Approach (Second Edition)
Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
Question
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Chapter 23, Problem 23.83QA
Interpretation Introduction

To find:

The equilibrium concentration of cysteine and penicillamine.

Expert Solution & Answer
Check Mark

Answer to Problem 23.83QA

Solution:

[Penicillamine] = 9.98×10-4 M

[Cysteine] = 1.00 M

Explanation of Solution

1) Concept:

The equilibrium reaction is:

CH3Hgpenicillamine+ aq+cysteine aq                 CH3Hgcysteine+ aq+penicillamine aq

The initial concentration of cysteine and CH3Hg(penicillamine)+ has been provided; therefore, we can calculate the equilibrium concentrations of the reactants and products using RICE table.

2) Formula:

Equilibrium constant K = CH3Hg(cysteine)+[penicillamine]CH3Hg(penicillamine)+[cysteine]

3) Given:

i) Initial concentration of cysteine =1.0 M

ii) Initial concentration of CH3Hg(penicillamine)+=1.0 mM= 1.0 ×10-3 M

iii) Equilibrium constant K=0.633

4) Calculations:

We can construct a RICE table to calculate the changes in the concentrations of products and reactants.

Reaction CH3Hg(penicillamine)+ aq +cysteine aq  CH3Hg(cysteine)+ aq +penicillamine (aq)
CH3Hgpenicillamine+  (M) [cysteine] (M) [CH3Hgcysteine+] (M) [penicillamine] (M)
Initial 1.0 ×10-3 1.0 0 0
Change - x - x + x + x
Equilibrium 1.0 ×10-3-x 1.0-x +x +x

Equilibrium constant K = CH3Hg(cysteine)+[penicillamine]CH3Hg(penicillamine)+[cysteine]

K= x ×x1.0 ×10-3-x × 1.0-x

Since we know the value of equilibrium constant, the change in the concentration can be calculated as below:

0.633= x21.0 ×10-3-x × 1.0-x

0.633 × 1.0 ×10-3-x × 1.0-x=x2

0.633 × 0.001-1.001x+x2=x2

0.000633-0.633633x+0.633x2=x2

0.367x2+0.633633x-0.000633=0

On solving the above quadratic equation, the value of  x is 9.984 ×10-4 M.

From the RICE table, we can see that the equilibrium concentration of penicillamine is equal to x=9.98×10-4 M.

The equilibrium concentration of cysteine is

 1.0 -xM=1.0- 9.9984 ×10-4M=0.999 M

Thus, the equilibrium concentration of penicillamine is 9.98 ×10-4M.

The equilibrium concentration of cysteine is 1.00 M.

Conclusion:

The equilibrium concentration of products and reactants can be calculated using the RICE table for the given equilibrium reaction.

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Chapter 23 Solutions

Chemistry: An Atoms-Focused Approach (Second Edition)

Ch. 23 - Prob. 23.11VPCh. 23 - Prob. 23.12VPCh. 23 - Prob. 23.13QACh. 23 - Prob. 23.14QACh. 23 - Prob. 23.15QACh. 23 - Prob. 23.16QACh. 23 - Prob. 23.17QACh. 23 - Prob. 23.18QACh. 23 - Prob. 23.19QACh. 23 - Prob. 23.20QACh. 23 - Prob. 23.21QACh. 23 - Prob. 23.22QACh. 23 - Prob. 23.23QACh. 23 - Prob. 23.24QACh. 23 - Prob. 23.25QACh. 23 - Prob. 23.26QACh. 23 - Prob. 23.27QACh. 23 - Prob. 23.28QACh. 23 - Prob. 23.29QACh. 23 - Prob. 23.30QACh. 23 - Prob. 23.31QACh. 23 - Prob. 23.32QACh. 23 - Prob. 23.33QACh. 23 - Prob. 23.34QACh. 23 - Prob. 23.35QACh. 23 - Prob. 23.36QACh. 23 - Prob. 23.37QACh. 23 - Prob. 23.38QACh. 23 - Prob. 23.39QACh. 23 - Prob. 23.40QACh. 23 - Prob. 23.41QACh. 23 - Prob. 23.42QACh. 23 - Prob. 23.43QACh. 23 - Prob. 23.44QACh. 23 - Prob. 23.45QACh. 23 - Prob. 23.46QACh. 23 - Prob. 23.47QACh. 23 - Prob. 23.48QACh. 23 - Prob. 23.49QACh. 23 - Prob. 23.50QACh. 23 - Prob. 23.51QACh. 23 - Prob. 23.52QACh. 23 - Prob. 23.53QACh. 23 - Prob. 23.54QACh. 23 - Prob. 23.55QACh. 23 - Prob. 23.56QACh. 23 - Prob. 23.57QACh. 23 - Prob. 23.58QACh. 23 - Prob. 23.59QACh. 23 - Prob. 23.60QACh. 23 - Prob. 23.61QACh. 23 - Prob. 23.62QACh. 23 - Prob. 23.63QACh. 23 - Prob. 23.64QACh. 23 - Prob. 23.65QACh. 23 - Prob. 23.66QACh. 23 - Prob. 23.67QACh. 23 - Prob. 23.68QACh. 23 - Prob. 23.69QACh. 23 - Prob. 23.70QACh. 23 - Prob. 23.71QACh. 23 - Prob. 23.72QACh. 23 - Prob. 23.73QACh. 23 - Prob. 23.74QACh. 23 - Prob. 23.75QACh. 23 - Prob. 23.76QACh. 23 - Prob. 23.77QACh. 23 - Prob. 23.78QACh. 23 - Prob. 23.79QACh. 23 - Prob. 23.80QACh. 23 - Prob. 23.81QACh. 23 - Prob. 23.82QACh. 23 - Prob. 23.83QACh. 23 - Prob. 23.84QACh. 23 - Prob. 23.85QACh. 23 - Prob. 23.86QACh. 23 - Prob. 23.87QACh. 23 - Prob. 23.88QACh. 23 - Prob. 23.89QACh. 23 - Prob. 23.90QACh. 23 - Prob. 23.91QACh. 23 - Prob. 23.92QACh. 23 - Prob. 23.93QACh. 23 - Prob. 23.94QACh. 23 - Prob. 23.95QACh. 23 - Prob. 23.96QA
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