Concept explainers
(A)
The
Answer to Problem 36QAP
The speed of light in ice is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of ice
Let the speed of light in ice be
Formula used:
Refractive Index of ice
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in ice is
(B)
The speed of light in acetone.
Answer to Problem 36QAP
The speed of light in acetone is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of acetone
Let the speed of light in acetone be
Formula used:
Refractive Index of acetone
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in acetone is
(C)
The speed of light in Plexiglas.
Answer to Problem 36QAP
The speed of light in Plexiglas is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Plexiglas
Let the speed of light in Plexiglas be
Formula used:
Refractive Index of Plexiglas
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Plexiglas is
(d)
The speed of light in Sodium Chloride.
Answer to Problem 36QAP
The speed of light in Sodium Chloride is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Sodium Chloride
Let the speed of light in Sodium Chloride be
Formula used:
Refractive Index of Sodium Chloride
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Sodium Chloride is
(E)
The speed of light in Sapphire.
Answer to Problem 36QAP
The speed of light in Sapphire is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Sapphire
Let the speed of light in Sapphire be
Formula used:
Refractive Index of Sapphire
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Sapphire is
(F)
The speed of light in diamond.
Answer to Problem 36QAP
The speed of light in diamond is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of diamond
Let the speed of light in diamond be
Formula used:
Refractive Index of diamond
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in diamond is
(G)
The speed of light in water.
Answer to Problem 36QAP
The speed of light in water is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of water
Let the speed of light in water be
Formula used:
Refractive Index of water
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in water is
(H)
The speed of light in crow glass.
Answer to Problem 36QAP
The speed of light in crow glass is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of crow glass
Let the speed of light in crow glass be
Formula used:
Refractive Index of crow glass
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in crow glass is
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Chapter 23 Solutions
COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
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- Construct Your Own Problem Consider sunlight entering the Earth’s atmosphere at sunrise and sunsetthat is, at a 90° incident angle. Taking the boundary between nearly empty space and the atmosphere to be sudden, calculate the angle of refraction for sunlight. This lengthens the time the Sun appears to be above the horizon, both at sunrise and sunset. Now construct a problem in which you determine the angle of refraction (or different models 01 the atmosphere, such as various layers of varying density. Your instructor may wish to guide you on the level of complexity to consider and on how the index at retraction varies with air density.arrow_forwardWhy is the front surface of a thermometer curved as shown? Figure 25.47 The curved surface of the thermometer serves a purpose.arrow_forwardThree sheets of plastic have unknown indices of refraction. Sheet 1 is placed on top of sheet 2, and a laser beam is directed onto the sheets from above so that it strikes the interface at an angle of 26.5 with the normal. The refracted beam in sheet 2 makes an angle of 31.7 with the normal. The experiment is repeated with sheet 3 on lop of sheet 2, and with the same angle of incidence, the refracted beam makes an angle of 36.7 with the normal. If the experiment is repeated again with sheet 1 on top of sheet 3, what is the expected angle of refraction in sheet 3? Assume the same angle of incidence.arrow_forward
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