‘Crystal field splitting energy’ should be identified. Concept introduction: Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows; E = hc λ where, h is planks constant c is speed of light λ is wavelength. Given: Wavelength of 295 nm for [Rh(NH 3 ) 6 ] 3+ ion.

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Answer 1

Question

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

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Answer 2

Question

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

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Answer 3

Question

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Expert Solution & Answer

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Answer 4

Question

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Expert Solution & Answer

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Answer 5

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 6

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 7

Chapter 23, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 23 - What is the electron configuration of the Cu+ ion?...Ch. 23 - Prob. 2SAQ Ch. 23 - Prob. 3SAQ Ch. 23 - Prob. 4SAQ Ch. 23 - Prob. 5SAQ Ch. 23 - Prob. 6SAQ Ch. 23 - Prob. 7SAQ Ch. 23 - Estimate the crystal field splitting energy (in...Ch. 23 - Use crystal field theory to determine the number...Ch. 23 - Prob. 10SAQ

Solution Summary: The author explains that the crystal field splitting energy (CFSE) is 40.610 4 kJ/mol.

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