A real battery is not just an emf. We can If model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the “internal resistance,” as shown in Figure P23.55. A typical battery has 1.0 Ω internal resistance due to imperfections that limit current through the battery. When there’s no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V. the value of the emf. Suppose the terminals of this battery are connected to a 2.0 Ω resistor. Figure P23.55 a. What is the potential difference between the terminals of the battery? b. What fraction of the battery’s power is dissipated by the internal resistance?
A real battery is not just an emf. We can If model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the “internal resistance,” as shown in Figure P23.55. A typical battery has 1.0 Ω internal resistance due to imperfections that limit current through the battery. When there’s no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V. the value of the emf. Suppose the terminals of this battery are connected to a 2.0 Ω resistor. Figure P23.55 a. What is the potential difference between the terminals of the battery? b. What fraction of the battery’s power is dissipated by the internal resistance?
A real battery is not just an emf. We can If model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the “internal resistance,” as shown in Figure P23.55. A typical battery has 1.0 Ω internal resistance due to imperfections that limit current through the battery. When there’s no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V. the value of the emf. Suppose the terminals of this battery are connected to a 2.0 Ω resistor.
Figure P23.55
a. What is the potential difference between the terminals of the battery?
b. What fraction of the battery’s power is dissipated by the internal resistance?
a. What is the potential difference across each resistor in Figure P23.6?b. Draw a graph of the potential as a function of the distance traveledthrough the circuit, traveling clockwise from V = 0 V at the lower left corner. See Figure P23.9 for an example of such a graph.
A circuit loop containing an external resistor of value R = 25.0 (ohms) is connected to a real battery with an internal emf = 20.0 V that has an internal resistance of R = 1.50 (ohms).
a. How much power is lost due to the internal resistance in the power supply, in Watts?
b. How much energy is lost in the external resistor (R), in Watts?
To maximize the percentage of the power from the emf of a battery that is delivered to a device external to the battery, what should the internal resistance of the battery be? (a) It should be as low as possible. (b) It should be as high as possible. (c) The percentage does not depend on the internal resistance.
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How To Solve Any Resistors In Series and Parallel Combination Circuit Problems in Physics; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=eFlJy0cPbsY;License: Standard YouTube License, CC-BY